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Anna007 [38]
2 years ago
7

Find the value of x in the triangle shown below. 2= 10 20 1160 10 17

Mathematics
1 answer:
WITCHER [35]2 years ago
5 0
32
In an isosceles triangle angles opposite to equal sides are equal
X+X+116=180
2X=180-116
X=64/2
X=32
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Flying against the wind, an airplane travels 4340 kilometers in 7 hours. Flying with the wind, the same plane travels 3120 kilom
Over [174]

The rate of the wind is given to be 210 the rate of the plane in mid air is given as 830

<h3>Howe to solve for the rate of the plane and wind</h3>

In 7 hours the kilometer traveled =  4340

P + W = 4340/7

= 620

P-W = 3120/3 hours

= 1040

2p = 1040 + 620

= 1660

p =830

W = 1040 - 830

= 210

Hence the rate of the wind is given to be 210 the rate of the plane in mid air is given as 830

Read more on rate here

brainly.com/question/24304697

#SPJ1

3 0
2 years ago
Pls help meh...... with the question.....pls it's urgent ...........​
HACTEHA [7]

Answer:

1.6962 = 1.70 (2 dp)

0.4247 = 0.425 to 3 dp

0.007395 = 0.007 to 3 dp

0.007395 = 0.0074 to 4 dp

32549 = 32500 to 3 significant figures

32549 = 32550 to 4 significant figures

909520 = 910000 to 3 significant figures

909520 = 909500 to 4 significant figures

Step-by-step explanation:

1.6962 = 1.70 (2 dp)

0.4247 = 0.425 to 3 dp

0.007395 = 0.007 to 3 dp

0.007395 = 0.0074 to 4 dp

32549 = 32500 to 3 significant figures

32549 = 32550 to 4 significant figures

909520 = 910000 to 3 significant figures

909520 = 909500 to 4 significant figures

5 0
3 years ago
Explain how to multiply the following whole numbers 21 x 14
Lesechka [4]

Answer:

\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}

________

\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}

Step-by-step explanation:

Given

21\:\times \:14

Line up the numbers

\begin{matrix}\space\space&2&1\\ \times \:&1&4\end{matrix}

Multiply the top number by the bottom number one digit at a time starting with the ones digit left(from right to left right)

Multiply the top number by the bolded digit of the bottom number

\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}

Multiply the bold numbers:    1×4=4

\frac{\begin{matrix}\space\space&2&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&4\end{matrix}}

Multiply the bold numbers:    2×4=8

\frac{\begin{matrix}\space\space&\textbf{2}&1\\ \times \:&1&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&8&4\end{matrix}}

Multiply the top number by the bolded digit of the bottom number

\frac{\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&8&4\end{matrix}}

Multiply the bold numbers:    1×1=1

\frac{\begin{matrix}\space\space&\space\space&2&\textbf{1}\\ \space\space&\times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&\space\space&8&4\\ \space\space&\space\space&1&\space\space\end{matrix}}

Multiply the bold numbers:    2×1=2

\frac{\begin{matrix}\space\space&\space\space&\textbf{2}&1\\ \space\space&\times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&\space\space&8&4\\ \space\space&2&1&\space\space\end{matrix}}

Add the rows to get the answer. For simplicity, fill in trailing zeros.

\frac{\begin{matrix}\space\space&\space\space&2&1\\ \space\space&\times \:&1&4\end{matrix}}{\begin{matrix}\space\space&0&8&4\\ \space\space&2&1&0\end{matrix}}

adding portion

\begin{matrix}\space\space&0&8&4\\ +&2&1&0\end{matrix}

Add the digits of the right-most column: 4+0=4

\frac{\begin{matrix}\space\space&0&8&\textbf{4}\\ +&2&1&\textbf{0}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{4}\end{matrix}}

Add the digits of the right-most column: 8+1=9

\frac{\begin{matrix}\space\space&0&\textbf{8}&4\\ +&2&\textbf{1}&0\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{9}&4\end{matrix}}

Add the digits of the right-most column: 0+2=2

\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}

Therefore,

\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}

________

\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}

6 0
3 years ago
You are driving home on a weekend from school at 55 mi/h for 110 miles. it then starts to snow and you slow to 35 mi/h. you arri
stepladder [879]

Okay lets get started.

I drove 110 miles with speed of 55 mi/hr so the time taken =

time = distance / speed

time = 110 / 55 = 2 hrs For the distance which is covered with 55 mi/hr speed.

Total time for reaching home is 4 hrs 15 minutes. (given in question)

Means rest distance after snow is covered in = 4 hrs 15 minutes - 2 hrs

= 2 hrs 15 minutes = 2 + 15/60 = 2.25 hrs

The speed in snow driving is 35 mi/hr

So distance covered in snow driving is = 2.25 * 35 = 78.75 miles

Hence the total distance = 110 + 78.75 = 188.75 miles : Answer

Hope that will help :)

6 0
3 years ago
What is the quadrilateral and triangle and square
S_A_V [24]
They are parallelogram  hopes that answer your question

5 0
3 years ago
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