Answer: increased
Step-by-step explanation:
- An x% confidence interval indicates that a person can be x% confident that true population parameter lies in it.
More level of confidence more width of the interval.
As level of Confidence interval increases width of interval increases.
Width of interval 
level of Confidence interval
So, If a 95% confidence interval had been constructed instead of 90% the width of the interval would have been<u> increased.</u>
Answer:
cosx= 35. Use Trignometrical identity cosx = √1−sin2x . cos x = √1−1625 = √925 = 35 to be the ...
Missing: =0.82 | Must include: =0.82
Step-by-step explanation:
Answer:
x = 9
y = 9√3 = 15.6
Step-by-step explanation:
The triangle given is a right triangle, therefore:
✔️apply trigonometric ratio formula to find x:
Reference angle = 60°
Hypotenuse = 18
Adjacent = x
Thus:
Cos (60) = x/18
Multiply both sides by 18
18×cos(60) = x
9 = x
x = 9
✔️find y by applying pythagorean theorem:
y² = 18² - x² (pythagorean theorem)
y² = 18² - 9² (substitution)
y² = 243
y = √243
y = √(81*3)
y = 9√3 = 15.6
Answer:
You already made an acc-
Step-by-step explanation:
Wdym?
Answer:
- (6-u)/(2+u)
- 8/(u+2) -1
- -u/(u+2) +6/(u+2)
Step-by-step explanation:
There are a few ways you can write the equivalent of this.
1) Distribute the minus sign. The starting numerator is -(u-6). After you distribute the minus sign, you get -u+6. You can leave it like that, so that your equivalent form is ...
(-u+6)/(u+2)
Or, you can rearrange the terms so the leading coefficient is positive:
(6 -u)/(u +2)
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2) You can perform the division and express the result as a quotient and a remainder. Once again, you can choose to make the leading coefficient positive or not.
-(u -6)/(u +2) = (-(u +2)-8)/(u +2) = -(u+2)/(u+2) +8/(u+2) = -1 + 8/(u+2)
or
8/(u+2) -1
Of course, anywhere along the chain of equal signs the expressions are equivalent.
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3) You can separate the numerator terms, expressing each over the denominator:
(-u +6)/(u+2) = -u/(u+2) +6/(u+2)
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4) You can also multiply numerator and denominator by some constant, say 3:
-(3u -18)/(3u +6)
You could do the same thing with a variable, as long as you restrict the variable to be non-zero. Or, you could use a non-zero expression, such as 1+x^2:
(1+x^2)(6 -u)/((1+x^2)(u+2))
