Pls help really important for my grade

48 girls, 41 boys, and 5 teachers sat in the gym. Write the ratio of girls to boys in three ways.

Anika [276]

Answer:

D

Step-by-step explanation:

The answer is D because the question is asking for girls to boys. So anything that has 5 in it is wrong because it isn't asking for teachers, which eliminates A. So since it is asking girls to boys the number order has to be 48 then 41 because it is asking for girls first then to boys. So that makes B wrong. When it comes to the fraction part of the ratio the first number it is asking for (which is girls) always goes on top. So that eliminates C which leaves only answer to be D.

7 0

3 years ago

When we plot all the points that satisfy an equation or inequality we what it?

Alex17521 [72]

When you GRAPH an equation or inequality you plot all of the points that satisfy it.

3 0

4 years ago

Please help this makes no sense to me

Whitepunk [10]

The answer to your question: the ratio of 4 months that have 30 days is ✨3 to 1✨

8 0

3 years ago

Read 2 more answers

A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as

Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let X = number of seconds in the batch.

The probability of the random variable X is, p = 0.31.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

$P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888$

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

$=1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776$

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

$={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453$

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0

3 years ago

At combs store there is a 25% chance a customer enters the store within one minute of closing time. Describe the complementary e

12345 [234]

The complementary event is that a customer does not enter the store within one minute of closing, and the probability is 75%.

The complement is found by subtracting from 100%; 100-25 = 75%.

6 0

4 years ago