The answer to the problem is as follows:
Count all boys as one unit. Then there is one boy and 2 girls who can be permuted in 3! = 6 ways. Bout the 3 boys can permute among themselves in 3! = 6 ways.
<span>6x6 = 36 ways in which all boys are together.
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Answer:
(−a+b)(−c+d)
=(−a+b)(−c+d)
=(−a)(−c)+(−a)(d)+(b)(−c)+(b)(d)
=ac−ad−bc+bd
A = pi * r^2
D = 2.5 so r = 1.25
A = 3.14 * 1.25^2
A = 4.9 ft^2
Answer:
D) 3
Step-by-step explanation:
22 * 2 = 44
To have a remainder 3, the number should be 44 + 3 = 47
47 ÷ 22 , leaves a remainder 3.
47 +22 = 69
69 ÷ 3 leaves a remainder 3.
69 +22 = 91
91 ÷ 3 leaves a remainder 3.
Answer: 47 , 69 , 91
