Let S(t) denote the amount of sugar in the tank at time t. Sugar flows in at a rate of
(0.04 kg/L) * (2 L/min) = 0.08 kg/min = 8/100 kg/min
and flows out at a rate of
(S(t)/1600 kg/L) * (2 L/min) = S(t)/800 kg/min
Then the net flow rate is governed by the differential equation
Solve for S(t):
The left side is the derivative of a product:
![\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/800}S(t)\right]=\dfrac8{100}e^{t/800}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dt%7D%5Cleft%5Be%5E%7Bt%2F800%7DS%28t%29%5Cright%5D%3D%5Cdfrac8%7B100%7De%5E%7Bt%2F800%7D)
Integrate both sides:
There's no sugar in the water at the start, so (a) S(0) = 0, which gives
and so (b) the amount of sugar in the tank at time t is
As 
, the exponential term vanishes and (c) the tank will eventually contain 64 kg of sugar.
Your answer would be x= -42
Say if you have 55/10 thats an improper fraction so in order to turn that into a mixed number divide 55 by 10 which you will get 5. Something right so the 5 will be your whole number 5 then your leftover is 5 so you will put that 5 over 10 so the mixed number will be 5 5/10 but you can simplify that to 5 1/2
Answer:
The distance of Satelite from the earth's surface = 2720.12 miles
Step-by-step explanation:
Below is the calculation for distance:
Use Pythagorean theorem
Distance, d² = 5400² + 4000²
d² = 45160000
d = 6720.12
Subtract the radius to find the distance from earth's surface.
Distance = 6720.12 - 4000 = 2720.12
The distance of Satelite from the earth's surface = 2720.12 miles
