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sashaice [31]
3 years ago
11

if the perimeter of the rectangle was known to be 90 in what would the value of x be in order for this to be true​

Mathematics
1 answer:
Fofino [41]3 years ago
8 0

Answer:

x = 30 in

Step-by-step explanation:

length of rectangle is (2/3)x + 10; width is (1/3)x + 5;

perimeter is 90 in; find x:

P = 90 in = 2(2/3)x + 2(10) + 2(1/3)x + 2(5), or

      90 in = (6/3)x + 30 in

Solving for x, we get (2)x = 60 in, or x = 30 in

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60%

Step-by-step explanation:

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8 0
3 years ago
How do you perform this: 2x+3y=25 3x+4y=22
meriva

Answer:

x = -34 , y = 31

Step-by-step explanation suing Gaussian elimination:

Solve the following system:

{2 x + 3 y = 25

3 x + 4 y = 22

Express the system in matrix form:

(2 | 3

3 | 4)(x

y) = (25

22)

Write the system in augmented matrix form and use Gaussian elimination:

(2 | 3 | 25

3 | 4 | 22)

Swap row 1 with row 2:

(3 | 4 | 22

2 | 3 | 25)

Subtract 2/3 × (row 1) from row 2:

(3 | 4 | 22

0 | 1/3 | 31/3)

Multiply row 2 by 3:

(3 | 4 | 22

0 | 1 | 31)

Subtract 4 × (row 2) from row 1:

(3 | 0 | -102

0 | 1 | 31)

Divide row 1 by 3:

(1 | 0 | -34

0 | 1 | 31)

Collect results:

Answer: {x = -34 , y = 31

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3 years ago
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Step-by-step explanation:

a

8 0
3 years ago
Read 2 more answers
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