What are the coordinates of P' when you translate P 3 units to the left and 1 unit up?

sveta [45]

You need to find the acceleration once the rope starts acting.

For that, first you need the velocity, V, when Karen ends the 2.0 m free fall

V^2 = Vo^2 + 2gd = 0^2 + 2* 9.81m/s^2 * 2.0 m = 39.24 m^2 / s^2 => V = 6.26 m/s

From that point, the rope starts acting with a net force that produces a constant acceleration, modeled as per these values and equation:

Vo = 6.26m/s
Vf = 0

Vf^2 = Vo^2 + 2ad => a = [Vf^2 - Vo^2] / 2d = [0^2 - (6.26 m/s)2 ] /2(1m) = -19.62 m/s^2

That acceleration is due to the difference of the force applied by the rope - the weight of Karen:

Weight of Karen: mg

Weight of karen - Force of the rope = Net force = ma

mg - Force of the rope = ma

Force of the rope = mg - ma = m(g -a) = m [9.81m/s^2 - (-19.62m/s^2) ]= 29.43m

To express it as a multiple of her weight, divide it by her weight (mg = 9.81m) =>

29.43m / 9.81m = 3.0

Answer: 3.0 times.

8 0

3 years ago

How in the world. Im terrible at math

ANEK [815]

B, because greater is to the left and right and because a greater or less than sign would indicate a spaced out line.

8 0

3 years ago

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Solve- cbb to work it out

zloy xaker [14]

<h3>Answers: </h3>

➝ Hypotenuse of triangle ( a ) = 21.63 mm

➝ Hypotenuse of triangle ( b ) = 150 mm

➝ Hypotenuse of triangle ( c ) = 111.80 mm

$\quad\rule{300pt}{1.5pt}\quad$

<h3>Solution:</h3>

We have to find the length of hypotenuse in the given 3 triangles, which can be done by using Pythagoras theorem.

Pythagoras theorem states that :

" In a right angled triangle, the square of hypotenuse side is equal to the sum of square of other two sides "

$\qquad \bull \:{\pmb{\mathfrak{ h^2 = b^2 + p^2}}}$

And we have to convert the answer to the units indicated in red i.e, in mm.

Since 1cm = 10 mm, we will convert the given values of length of side in mm before putting the values in the formula

For triangle ( a )

$:\implies\qquad \sf{ h^2 = b^2 + p^2}$

$:\implies\qquad \sf{ h =\sqrt{b^2 + p^2}}$

$:\implies\qquad \sf{h=\sqrt{ (12)^2 + (18)^2 }}$

$:\implies\qquad \sf{ h= \sqrt{144 + 324}}$

$:\implies\qquad \sf{ h = \sqrt{468}}$

$:\implies\qquad\underline{\underline{\pmb{ \sf{ h = 21.63 mm}}}}$

For triangle ( b )

$:\implies\qquad \sf{ h^2 = b^2 + p^2}$

$:\implies\qquad \sf{h =\sqrt{b^2 + p^2} }$

$:\implies\qquad \sf{ h = \sqrt{(90)^2+(120)^2}}$

$:\implies\qquad \sf{ h=\sqrt{8100+14400}}$

$:\implies\qquad \sf{ h =\sqrt{22500}}$

$:\implies\qquad\underline{\underline{\pmb{ \sf{h = 150mm}}} }$

For triangle ( c )

$:\implies\qquad \sf{h^2 = b^2 + p^2 }$

$:\implies\qquad \sf{ h=\sqrt{b^2 + p^2}}$

$:\implies\qquad \sf{ h =\sqrt{(100)^2)+(50)^2}}$

$:\implies\qquad \sf{ h=\sqrt{10000+2500}}$

$:\implies\qquad \sf{ h =\sqrt{12500}}$

$:\implies\qquad \underline{\underline{\pmb{\sf{h = 111.80mm}}} }$

4 0

1 year ago

Match the term with the definition. . . -perpendicular cross section of a pyramid. -perpendicular cross section of a cylinder. -

My name is Ann [436]

The correct answers are:

Perpendicular cross-section of a pyramid is a triangle.
Perpendicular cross-section of an oblique cylinder is an ellipse.
Parallel cross-section of a sphere is a circle.
When a rectangle is rotated about the y-axis, a cylinder is formed.
When a right triangle is rotated about the y-axis, a cone is formed.

Explanation:

Cutting a cross-section of a pyramid perpendicular to the base would form a triangle. Your "slice" would go from the apex of the pyramid straight to the base. Where the cut goes through the slanted faces of the pyramid would form the slanted sides of the triangle. Where the cut goes through the base of the pyramid would make the base of the triangle.

Cutting a cross-section of an oblique (non-right) cylinder would form an ellipse (oval). Since the cylinder is not right, it is slanted. This means going perpendicular to the base of the cylinder would not go straight (horizontally) through the cylinder; instead it slants, which "stretches" the cross-section, forming an ellipse.

Any cross-section of a sphere is a circle, since a sphere is perfectly round with no base.

When rotating a rectangle about the y-axis, imagine rotating a piece of paper. The shape formed by doing this would "bend" the rectangle around the axis, forming a cylindrical shape.

When rotating a triangle about the y-axis, we can imagine the same situation we did with the rectangle; the difference is that the triangle goes in a point, which means this new figure will be as well. This would make it a cone rather than a cylinder.

5 0

2 years ago

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Pls explain how to do this

yulyashka [42]

find the value of x. if x is 2 for example multiply that 6 times to find the numerator. 2 x 2 x 2 x 2 x 2 x2 = 64. multiply that with 3 which is 192. now to find the denominator you are going to multiply 2 three times. 2 x 2 x2 = 8. now divide the denominator with the numerator which equals 8.

6 0

2 years ago

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