Answer:
x-intercept: <u>(1,0)</u>
y-intercept: <u>(0,1)</u>
Step-by-step explanation:
Given: Find the x and y intercepts of 2x + 2y = 2
<h2><u>X-intercept</u></h2>
To solve for a x - intercept we have to substitue 0 in for y and solve for 
Lets do it:
2x + 2(0) = 2
2x + 0 = 2
2x = 2
x = 1
Therefore, this means that when y = 0, x = 1 or (1,0)
<h2><u>Y-intercept</u></h2>
To solve for a y - intercept we have to substitue 0 in for x and solve for 
Lets do it:
2(0) + 2y = 2
0 + 2y = 2
2y = 2
y = 1
Therefore, this means that when x = 0, y = 1 or (0,1)
Answer:
x=2
Step-by-step explanation:
2x+4=8
2x=8-4
2x=4
x=4/2
x=2
Answer:
B
Step-by-step explanation:
Answer:
x = 4
Step-by-step explanation:
5[3(x + 4) - 2(1 - x)] - x - 25 = 14x + 65
Distribute by 3 and 2 inside the square bracket
5 [ 3x + 12 - 2 + 2x ] - x - 25 = 14x + 65
collect like terms inside the square bracket
5 (5x + 10) - x - 25 = 14x + 65 ← distribute the parenthesis by 5
25x + 50 - x - 25 = 14x + 65 ← collect like terms on left side
24x + 25 = 14x + 65 ( subtract 14x from both sides )
10x + 25 = 65 ( subtract 25 from both sides )
10x = 40 ( divide both sides by 10 )
x = 4
