Answer:
The points when graphed are: (3,0) and (0,-5)
Step-by-step explanation:
I know that these points are a solution to the graph because it has one x value and one y value that stays constant.
For an example, if we used an X and Y table we could see that each variable has one other variable.
This is how it look like when graphed:
Answer:
4
Step-by-step explanation:
plug 1 into the equation and get
-2(1)^2 +2(1) +4
simplify
-2+2+4
add
4
Hi there!
»»————- ★ ————-««
I believe your answer is:
{1, 2, 3, 4, 6, 9, 12, 18, 36}
»»————- ★ ————-««
Here’s why:
A factor is a whole number that is multiplied by another to have a product have another number.
⸻⸻⸻⸻
The Factors Are:
- 1 (1 * 36 = 36)
- 2 (2 * 18 = 36)
- 3 (3 * 12 = 36)
- 4 (4 * 9 = 36)
- 6 (6 * 6 = 36)
- 9 (9 * 4 = 36)
- 12 (12 * 3 = 36)
- 18 (18 * 2 = 36)
- 36 (36 * 1 = 36)
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
the probability that the sample mean will be smaller than m = 22 is 0.02275.
For the given question,
A z-score measures exactly how many standard deviations a data point is above or below the mean. It allows us to calculate the probability of a score occurring within our normal distribution and enables us to compare two scores that are from different normal distributions.
Here sample size, n = 4
mean, μ = 30
standard deviation, σ = 8
The probability that the sample mean will be smaller than m = 22 is
z = 
⇒ z =
⇒ z = 
⇒ z = 
⇒ z = -2
Refer the Z table for p value,
Thus for P(z < -2) is 0.02275.
Hence we can conclude that the probability that the sample mean will be smaller than m = 22 is 0.02275.
Learn more about probability of the sample mean here
brainly.com/question/16897081
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Answer:

Step-by-step explanation:
see the attached figure with letters to better understand the problem
step 1
Find the measure of arc BC
we know that
----> by complete circle
substitute the given values



step 2
Find the measure of angle 2
we know that
The inscribed angle is half that of the arc it comprises.
so
![m\angle 2=\frac{1}{2}[arc\ BC]](https://tex.z-dn.net/?f=m%5Cangle%202%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20BC%5D)
substitute
![m\angle 2=\frac{1}{2}[116^o]=58^o](https://tex.z-dn.net/?f=m%5Cangle%202%3D%5Cfrac%7B1%7D%7B2%7D%5B116%5Eo%5D%3D58%5Eo)