<span>B. It must be the same as when he constructed the arc centered at point A.
This problem would be a lot easier if you had actually supplied the diagram with the "arcs shown". But thankfully, with a few assumptions, the solution can be determined.
Usually when constructing a perpendicular to a line through a specified point, you first use a compass centered on the point to strike a couple of arcs on the line on both sides of the point, so that you define two points that are equal distance from the desired intersection point for the perpendicular. Then you increase the radius of the compass and using that setting, construct an arc above the line passing through the area that the perpendicular will go. And you repeat that using the same compass settings on the second arc constructed. This will define a point such that you'll create two right triangles that are reflections of each other. With that in mind, let's look closely at your problem to deduce the information that's missing.
"... places his compass on point B ..."
Since he's not placing the compass on point Q, that would imply that the two points on the line have already been constructed and that point B is one of those 2 points. So let's look at the available choices and see what makes sense.
A .It must be wider than when he constructed the arc centered at point A.
Not good. Since this implies that the arc centered on point A has been constructed, then it's a safe assumption that points A and B are the two points defined by the initial pair of arcs constructed that intersect the line and are centered around point Q. If that's the case, then the arc centered around point B must match exactly the setting used for the arc centered on point A. So this is the wrong answer.
B It must be the same as when he constructed the arc centered at point A.
Perfect! Look at the description of creating a perpendicular at the top of this answer. This is the correct answer.
C. It must be equal to BQ.
Nope. If this were the case, the newly created arc would simply pass through point Q and never intersect the arc centered on point A. So it's wrong.
D.It must be equal to AB.
Sorta. The setting here would work IF that's also the setting used for the arc centered on A. But that's not guaranteed in the description above and as such, this is wrong.</span>
Answer:
x + 1
y = 9
Step-by-step explanation:
In order to solve this question we need to represent "y "in terms of "x" in the first equation, and the plug in the "y" value in the first equation into the second one. Luckily for us in the first equation it already shows what "y" is equal to in terms of "x" (based on the first equation y = -x + 10). Now we just need to plug in the value that we got instead of "y" in the second equation, and so we get....
y = 7x + 2
(plug in the y value and get the following ….)
-x + 10 = 7x + 2
(now just solve the following equation)
-x + 10 + x = 7x + 2 + x
10 = 8x + 2
10 - 2 = 8x + 2 - 2
8 = 8x
8/8 = 8x/8
1 = x
Now that we know the value of "x", all we need to do now is substitute the value of "x" into any of the equations and we will get the value of "y". So we do the following.....
y = 7x + 2
y = 7(1) + 2
y = 7 + 2
y = 9
Answer:
The person walked 1,056 feet in 6 minutes.
Mph 12
Answer:
x=11.5 i think
Step-by-step explanation:
Answer:
X=-4, Y=22, idk about the CBD
Step-by-step explanation:
4y+2=90 degrees
subtract 2 on both sides you would get
4y=88 divide 4 with 88 and get 22
solve both X's so 5x+6=3x-2
i would subtract 3x first so i can get
2x+6=-2
then subtract 6 on both sides so you would have
2x=-8 divide -8 with 2 and get -4
