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3 years ago

7

Find the area. The area of the trapezoid is square centimeters.fill in the blank

1 answer:

OlgaM077 [116]3 years ago

5 0

Answer:

the answer is 35. hope this helps :))

Step-by-step explanation:

the formula is A= 1/2(b1+ b2)h

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In Exercise, describe how the graph of g is related to the graph of f.<br> g(x)=-1+f(x)

Jet001 [13]

Answer:

The graph of g is the graph of f shifted down 1 unit.

Step-by-step explanation:

Suppose you have a function y = f(x), you can do these following operations on the function:

Shift up a units: y = f(x) + a

Shift down a units: y = f(x) - a

Shift left a units: y = f(x + a)

Shift right a units: y = f(x - a)

In this problem, we have that:

g(x) = -1 + f(x) = f(x) - 1

So the graph of g is the graph of f shifted down 1 unit.

7 0

3 years ago

Lagrange multipliers have a definite meaning in load balancing for electric network problems. Consider the generators that can o

Ivahew [28]

Answer:

The load balance $(x_1,x_2,x_3)=(545.5,272.7,181.8)$ Mw minimizes the total cost

Step-by-step explanation:

<u>Optimizing With Lagrange Multipliers</u>

When a multivariable function f is to be maximized or minimized, the Lagrange multipliers method is a pretty common and easy tool to apply when the restrictions are in the form of equalities.

Consider three generators that can output xi megawatts, with i ranging from 1 to 3. The set of unknown variables is x1, x2, x3.

The cost of each generator is given by the formula

$\displaystyle C_i=3x_i+\frac{i}{40}x_i^2$

It means the cost for each generator is expanded as

$\displaystyle C_1=3x_1+\frac{1}{40}x_1^2$

$\displaystyle C_2=3x_2+\frac{2}{40}x_2^2$

$\displaystyle C_3=3x_3+\frac{3}{40}x_3^2$

The total cost of production is

$\displaystyle C(x_1,x_2,x_3)=3x_1+\frac{1}{40}x_1^2+3x_2+\frac{2}{40}x_2^2+3x_3+\frac{3}{40}x_3^2$

Simplifying and rearranging, we have the objective function to minimize:

$\displaystyle C(x_1,x_2,x_3)=3(x_1+x_2+x_3)+\frac{1}{40}(x_1^2+2x_2^2+3x_3^2)$

The restriction can be modeled as a function g(x)=0:

$g: x_1+x_2+x_3=1000$

Or

$g(x_1,x_2,x_3)= x_1+x_2+x_3-1000$

We now construct the auxiliary function

$f(x_1,x_2,x_3)=C(x_1,x_2,x_3)-\lambda g(x_1,x_2,x_3)$

$\displaystyle f(x_1,x_2,x_3)=3(x_1+x_2+x_3)+\frac{1}{40}(x_1^2+2x_2^2+3x_3^2)-\lambda (x_1+x_2+x_3-1000)$

We find all the partial derivatives of f and equate them to 0

$\displaystyle f_{x1}=3+\frac{2}{40}x_1-\lambda=0$

$\displaystyle f_{x2}=3+\frac{4}{40}x_2-\lambda=0$

$\displaystyle f_{x3}=3+\frac{6}{40}x_3-\lambda=0$

$f_\lambda=x_1+x_2+x_3-1000=0$

Solving for \lambda in the three first equations, we have

$\displaystyle \lambda=3+\frac{2}{40}x_1$

$\displaystyle \lambda=3+\frac{4}{40}x_2$

$\displaystyle \lambda=3+\frac{6}{40}x_3$

Equating them, we find:

$x_1=3x_3$

$\displaystyle x_2=\frac{3}{2}x_3$

Replacing into the restriction (or the fourth derivative)

$x_1+x_2+x_3-1000=0$

$\displaystyle 3x_3+\frac{3}{2}x_3+x_3-1000=0$

$\displaystyle \frac{11}{2}x_3=1000$

$x_3=181.8\ MW$

And also

$x_1=545.5\ MW$

$x_2=272.7\ MW$

The load balance $(x_1,x_2,x_3)=(545.5,272.7,181.8)$ Mw minimizes the total cost

5 0

4 years ago

Which functions can generate all the values in table 2

Whitepunk [10]

Answer:

animania-1.12.2-1.6.2.jar

4 0

3 years ago

Brown bats sleep for 20 hours each day. How many hours per week are they awake? How many hours per year are they awake

icang [17]

(20)(7) = 140 hours per week
(20)(365) = 7300 hours per year

7 0

3 years ago

Candice is deep-sea diving with two friends. Whitney is exploring a coral reef 56 feet in front of Candice, and Ed is floating o

Mekhanik [1.2K]

Answer:

126

Step-by-step explanation:

70

<u>+ 56</u>

126

5 0

3 years ago