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3 years ago

F(x)= {2ˆx, X<0 {-xˆ2 -4x +1, 0 2

Mathematics

1 answer:

N76 [4]3 years ago

5 0

Answer: If x is less than 0, 2 to the power of that negative x will be 1/2^x.

So, 1/2^x.

Step-by-step explanation:

I can't go any further without more info about value of x.

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evablogger [386]

Step-by-step explanation:

Area of circle = pi r²

Area of half circle = pi r²/2

= 3.142 × 10²/ 2

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4 years ago

What is the value of x in the equation 7x - 30 = 180

solong [7]

X=30

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3 years ago

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ABC ~ XYZ Find the length of BC (need an answer as soon as possible, with showing work please)

Snezhnost [94]

Answer:

BC is equal to 7

Step-by-step explanation:

18 = 2x + 4

18 - 4 = 14

14 = 2x

14/2 = 7

7 = x

4 0

3 years ago

imagine you're in a queue to the airport check-in desk if two-thirds of the queue is in front of you and three tenths of the que

lawyer [7]

2/3 in front x10
3/10 behind x3

20/30 In front
9/30 behind

20/30+9/30= 29/30
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3 years ago

Read 2 more answers

Express the fifth roots of unity in standard form a + bi. with 1 + 0i

marishachu [46]

Answer:

For K=0

$cos(\frac{0+2\pi 0}{5})+isin(\frac{0+2\pi 0}{5})\\cos(0)+isin(0)=1+i0$

For K=1:

$cos(\frac{0+2\pi 1}{5})+isin(\frac{0+2\pi 1}{5})\\cos(2\pi/5)+isin(2\pi/5)=0.3090+i0.9510$

For K=2:

$cos(\frac{0+2\pi 2}{5} )+isin(\frac{0+2\pi 2}{5} )\\cos(4\pi/5)+isin(4\pi/5)=-0.809+i0.587$

For K=3:

$cos(\frac{0+2\pi 3}{5} )+isin(\frac{0+2\pi 3}{5} )\\cos(6\pi/5)+isin(6\pi/5)=-0.809-i0.587$

For K=4:

$cos(\frac{0+2\pi 4}{5} )+isin(\frac{0+2\pi 4}{5} )\\cos(8\pi/5)+isin(8\pi/5)=0.3091-i0.9510$

Step-by-step explanation:

Fifth Root is given by:

$\sqrt[5]{z}=1+0i$

The above equation will become:

$z=(1+0i)^5$

It can be written as:

$z=[cos(0)+isin(0)]^5$

|z|=1,

According to De-moivre's Theorem:

$z=cos(\frac{0}{5})+isin(\frac{0}{5})\\ z=cos(0)+isin(0)$

Now, Fifth Roots of unity in standard form a + bi :

$\sqrt[5]{z}=[{cos(0+2\pi k)+isin(0+2\pi k)}]^{1/5}$

k=0,1,2,3,4

For K=0

$cos(\frac{0+2\pi 0}{5})+isin(\frac{0+2\pi 0}{5})\\cos(0)+isin(0)=1+i0$

For K=1:

$cos(\frac{0+2\pi 1}{5})+isin(\frac{0+2\pi 1}{5})\\cos(2\pi/5)+isin(2\pi/5)=0.3090+i0.9510$

For K=2:

$cos(\frac{0+2\pi 2}{5} )+isin(\frac{0+2\pi 2}{5} )\\cos(4\pi/5)+isin(4\pi/5)=-0.809+i0.587$

For K=3:

$cos(\frac{0+2\pi 3}{5} )+isin(\frac{0+2\pi 3}{5} )\\cos(6\pi/5)+isin(6\pi/5)=-0.809-i0.587$

For K=4:

$cos(\frac{0+2\pi 4}{5} )+isin(\frac{0+2\pi 4}{5} )\\cos(8\pi/5)+isin(8\pi/5)=0.3091-i0.9510$

6 0

3 years ago