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zhannawk [14.2K]
3 years ago
10

30 POINTS PLEASE HELP2 QUESTIONS

Mathematics
2 answers:
zavuch27 [327]3 years ago
8 0

x^2 + 14x = 32

To make a perfect square, you need to add 49 to both sides

x^2 + 14x + 49 = 32 + 49

Answer:  49

Solve:

x^2 + 14x + 49 = 32 + 49

(x + 7)^2 = 81

(x + 7)^2 = 9^2

So

x + 7 = 9

x = 2

and

x + 7 = -9

x = -16

Answer:

x = 2 and x = -16

Thepotemich [5.8K]3 years ago
3 0

Answer:

2 and -16

Step-by-step explanation:

https://www.tiger-algebra.com/drill/x~2_14x=32/

"Two solutions were found :

x = 2

x = -16

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    x^2+14*x-(32)=0

Step by step solution :

Step  1  :

Trying to factor by splitting the middle term

1.1     Factoring  x2+14x-32

The first term is,  x2  its coefficient is  1 .

The middle term is,  +14x  its coefficient is  14 .

The last term, "the constant", is  -32

Step-1 : Multiply the coefficient of the first term by the constant   1 • -32 = -32

Step-2 : Find two factors of  -32  whose sum equals the coefficient of the middle term, which is   14 .

     -32    +    1    =    -31

     -16    +    2    =    -14

     -8    +    4    =    -4

     -4    +    8    =    4

     -2    +    16    =    14    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -2  and  16

                    x2 - 2x + 16x - 32

Step-4 : Add up the first 2 terms, pulling out like factors :

                   x • (x-2)

             Add up the last 2 terms, pulling out common factors :

                   16 • (x-2)

Step-5 : Add up the four terms of step 4 :

                   (x+16)  •  (x-2)

            Which is the desired factorization

Equation at the end of step  1  :

 (x + 16) • (x - 2)  = 0 "

       

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A student has $5.00 to spend on a poster, paint, and stickers. The total cost for the
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Answer:

2.8+.55x=5 x=4

Step-by-step explanation:

5-2.8=2.2

2.2/.55=4

4 0
3 years ago
Solve for x. enter your answer in interval notation using grouping symbols. x^2+15x<-36
Oliga [24]
X²+15x+36<0

at first solve quadratic equation

D=b²-4ac= 225-4*1*36= 81

x=(-b+/-√D)/2a
x=(-15+/-√81)/2= (-15+/-9)/2
x1=(-15-9)/2=-12
x2=(-15+9)/2=-3

we can write x²+15x+36<0 as (x+12)(x+3)<0

(x+12)(x+3)<0 can be 2 cases, because for product to be negative one factor should be negative , and second factor should be positive
 1 case)      x+12<0, and x+3>0,                                            
                       x<-12, and x>-3
(-∞, -12) and(-3,∞) gives empty set

or second case)  x+12>0 and x+3<0
x>-12 and x<-3
(-12,∞) and (-∞,-3)  they are crossing , so (-12, -3)  is a solution of this inequality


3 0
4 years ago
A random sample of 100 people from City A has an average IQ of 120 with a SD of 18. Independently of this, a random sample of 15
Sloan [31]

Answer:

z=\frac{(120-116)-0}{\sqrt{\frac{18^2}{100}+\frac{15^2}{150}}}}=1.837

p_v =P(z>1.837)=1-P(Z  

Comparing the p value with a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the average IQ on city A is signficantly higher than city B at 5% of singificance.  

Step-by-step explanation:

\bar X_{A}=120 represent the mean for sample 1

\bar X_{B}=116 represent the mean for sample 2

s_{A}=18 represent the sample standard deviation for 1  

s_{B}=15 represent the sample standard deviation for 2  

n_{A}=100 sample size for the group 2  

n_{B}=150 sample size for the group 2  

\alpha Significance level provided

z would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if residents of City A smarter on average, the system of hypothesis would be:  

Null hypothesis:\mu_{A}-\mu_{B}\leq 0  

Alternative hypothesis:\mu_{A} - \mu_{B}> 0  

We don't have the population standard deviation's, but the sample sizes are large enough we can apply a z test to compare means, and the statistic is given by:  

z=\frac{(\bar X_{A}-\bar X_{B})-\Delta}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}} (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:  

z=\frac{(120-116)-0}{\sqrt{\frac{18^2}{100}+\frac{15^2}{150}}}}=1.837

P value

Since is a one right tailed test the p value would be:  

p_v =P(z>1.837)=1-P(Z  

Comparing the p value with a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the average IQ on city A is signficantly higher than city B at 5% of singificance.  

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Step-by-step explanation:

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Step-by-step explanation:

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