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iragen [17]
3 years ago
12

Solving each system by Eliminating x-y-2z=4 -x+2y+z=1 -x+y-3z=11

Mathematics
1 answer:
elena-s [515]3 years ago
3 0

Answer:

<em>x = 0 </em>

<em>y = 2</em>

<em>z = -3</em>

Step-by-step explanation:

x-y-2z=4     (1)

-x+2y+z=1   (2)

-x+y-3z=11  (3)

(1) + (3) = x-y-2z + (-x)+y-3z   = 4+11

           = -5z                          = 15

-> z = -3

(1) + (2) = x - y - 2z + (-x) + 2y + z = 4+1

           = y-z                                 = 5

           = y- (-3)                             = 5

-> y = 2

(1) = x-y-2z            = 4  

   = x - 2 - 2 * (-3) = 4

-> x = 0

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