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3 years ago

Solving each system by Eliminating x-y-2z=4 -x+2y+z=1 -x+y-3z=11

Mathematics

1 answer:

elena-s [515]3 years ago

3 0

Answer:

x = 0

y = 2

z = -3

Step-by-step explanation:

x-y-2z=4 (1)

-x+2y+z=1 (2)

-x+y-3z=11 (3)

(1) + (3) = x-y-2z + (-x)+y-3z = 4+11

= -5z = 15

-> z = -3

(1) + (2) = x - y - 2z + (-x) + 2y + z = 4+1

= y-z = 5

= y- (-3) = 5

-> y = 2

(1) = x-y-2z = 4

= x - 2 - 2 * (-3) = 4

-> x = 0

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