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ANEK [815]
3 years ago
14

A survey was conducted to determine the popularity of three foods among students. The data collected from 75 students are summar

ized above. What is the number of students who like none or only one of the foods?
Mathematics
1 answer:
Andrews [41]3 years ago
4 0

Answer:

20

Step-by-step explanation:

Total no = 75

N (P) = 48 , N (H) = 45 , N (T) = 58

N (P∩H) = 28 , N (H∩T) = 37 , N (P∩T) = 40

N (P∩H∩T) = 25

Total no = N (P) + N (H) + N (T) - N (P∩H)  -  N (H∩T) - N (P∩T) + N (P∩H∩T) + neither

75 = 48 + 45 + 58 - 28 - 37 - 40 + 25 + neither

75 = 71 + neither → neither = 4

N (only P) = N (P) - N (P∩H)  - N (P∩T)  + N (P∩H∩T) = 48 - 28 - 40 + 25 = 5

N (only H) = N (H) - N (P∩H) - N (H∩T) +  N (P∩H∩T) = 45 - 28 - 37 + 25 = 5

N (only T) = N (T) - N (H∩T) - N (P∩T) + N (P∩H∩T) = 58 - 37 - 40 + 25 = 6

So, total liking either one or neither = 4 + 5 + 5 + 6 = 20

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Answer:

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Step-by-step explanation:

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2. you multiply and then simplify so first you have 30j+12+6j, so you add like terms so... 30j+6j= 36j and then +12

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