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ZanzabumX [31]
3 years ago
13

A won a race at the local fair by running 10.5 miles in exactly 2 hours. At this constant​ rate, how long does it take the same

dog to run the 21 mile state fair​ race? Use ratio reasoning to solve. * 1 point
Mathematics
1 answer:
Luba_88 [7]3 years ago
3 0

Answer:

The dog will run the 21-mile race in 4.04 hours

Step-by-step explanation:

The first thing we need to do is find out how far he ran the race at the local fair in 1 hour.

To do this, we can set up a simple relationship:

If he ran 10.5 miles in 2 hours,

He will run x miles in 1 hour

Cross multiplying, we have

x = (10.5 X 1)/2 = 5.25 miles in 1 hour.

We can now comfortably say that he runs at the rate of 5.2miles/hr

He now goes to the state fair race, which is 21 miles long.

if he runs at the rate of 5.2 miles in 1 hour,

He will run 21 miles in y hours

y = 21 / 5.2 = 4.04 hours

The dog will run the 21-mile race in 4.04 hours

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liberstina [14]

Answer:

the answer is (-4, 5)

Step-by-step explanation:

Let's use elimination by addition / subtraction:

-6x - 2y =  14

6x + 7y = 11

-------------------

        5y   = 25, so y = 5.

Substituting 5 for y in the 2nd equation, we get:

6x + 7(5) = 11, or:

6x + 35 = 11, or

6x = -24, or x = -4.

Thus, the answer is (-4, 5).  Please double check to ensure you have copied down both system of equations and answer correctly.

Check:  Is (-4, 5) a solution to this system?

Subst. -4 for x and 5 for y in the first equation:

            -3(-4) - (5) = 7

               12 - 5 = 7  YES

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3 years ago
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tatyana61 [14]
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4 0
3 years ago
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