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ZanzabumX [31]
3 years ago
13

A won a race at the local fair by running 10.5 miles in exactly 2 hours. At this constant​ rate, how long does it take the same

dog to run the 21 mile state fair​ race? Use ratio reasoning to solve. * 1 point
Mathematics
1 answer:
Luba_88 [7]3 years ago
3 0

Answer:

The dog will run the 21-mile race in 4.04 hours

Step-by-step explanation:

The first thing we need to do is find out how far he ran the race at the local fair in 1 hour.

To do this, we can set up a simple relationship:

If he ran 10.5 miles in 2 hours,

He will run x miles in 1 hour

Cross multiplying, we have

x = (10.5 X 1)/2 = 5.25 miles in 1 hour.

We can now comfortably say that he runs at the rate of 5.2miles/hr

He now goes to the state fair race, which is 21 miles long.

if he runs at the rate of 5.2 miles in 1 hour,

He will run 21 miles in y hours

y = 21 / 5.2 = 4.04 hours

The dog will run the 21-mile race in 4.04 hours

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Solve for x. <br><br> x + 3x + 5 =21
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Answer:

x=4

Step-by-step explanation:

In order to solve for x, we must isolate x on one side of the equation.

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First, combine like terms. x and 3x are both terms with variables, and can be combined.

(x+3x) + 5=21

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5 is being added to 4x. The inverse of addition is subtraction. Subtract 5 from both sides of the equation.

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x is being multiplied by 4. The inverse of multiplication is division. Divide both sides by 4.

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Let's check our solution. Plug 4 in for x and solve.

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This solution checks out, so we know our answer is correct.

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