Complete question is;
The terminal side of angle θ in standard position, intersects the unit circle at P(-10/26, -24/26). What is the value of csc θ?
Answer:
csc θ = -13/12
Step-by-step explanation:
We know that in a unit circle;
(x, y) = (cos θ, sin θ)
Since the the terminal sides intersects P at the coordinates P(-10/26, -24/26), we can say that;
cos θ = -10/26
sin θ = -24/26
Now we want to find csc θ.
From trigonometric ratios, csc θ = 1/sin θ
Thus;
csc θ = 1/(-24/26)
csc θ = -26/24
csc θ = -13/12
From the given triangle in the photo, the lengths of the sides are 3m and a, the hypotenuse is c. One angle, opposite of 3m is given to be 50 degrees C. The right equation that would solve c is,
sin (50 degrees C) = 3m / c
Thus, the answer is the first choice.
Answer:
C. f(-1) =12
Step-by-step explanation:
f(x)= 3x^2+9
Let x=-1
f(-1) = 3(-1)^2 +9
= 3(1)+9
= 3+9
= 12
f(-1) =12
The perimeter of parallelogram WXYZ is 22
