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slava [35]
3 years ago
11

Terry had $43 in a checking account. If Terry writes a check for $62, what is the new account balance? a. $105 c. -$19 b. $19 d.

-$9
Mathematics
1 answer:
Keith_Richards [23]3 years ago
4 0
Terry has 43 in her checking account....she then writes a check for 62...
43 - 62 = - 19 <==
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From a random sample of 58 businesses, it is found that the mean time the owner spends on administrative issues each week is 21.
zzz [600]

Answer: (20.86, 22.52)

Step-by-step explanation:

Formula to find the confidence interval for population mean :-

\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}

, where \overline{x} = sample mean.

z*= critical z-value

n= sample size.

\sigma = Population standard deviation.

By considering the given question , we have

\overline{x}= 21.69

\sigma=3.23

n= 58

Using z-table, the critical z-value for 95% confidence = z* = 1.96

Then, 95% confidence interval for the amount of time spent on administrative issues will be :

21.69\pm (1.96)\dfrac{3.23}{\sqrt{58}}

=21.69\pm (1.96)\dfrac{1.7}{7.61577}

=21.69\pm (1.96)(0.223221)

\approx21.69\pm0.83

=(21.69-0.83,\ 21.69+0.83)=(20.86,\ 22.52)

Hence, the 95% confidence interval for the amount of time spent on administrative issues = (20.86, 22.52)

7 0
3 years ago
Can you please help answer will make you brainliest
Nady [450]

Answer:

C

Step-by-step explanation:

given a triangle with 2 sides and the angle between them given, then the area (A) is calculated as

A = \frac{1}{2} bc sinA

the 2 sides are b = 4, c = 6 and ∠ A = 35° , then

A = \frac{1}{2} × 4 × 6 × sin35° = 12 × sin35° ≈ 6.9 m² ( to the nearest tenth )

7 0
2 years ago
Marking people as BRAINLIST
Gnesinka [82]

Answer:

66

Step-by-step explanation:

57 x 2= 114

180-114= 66

5 0
2 years ago
Guys, Can you please help me with these questions
MakcuM [25]

Answer:

a) w^{13} x^{5} y^{6}

b) \frac{x}{3y^{6} }

Step-by-step explanation:

a) (w^{2} xy^{3} )^{2}(w^{3}x )^{3}

1. Distribute the second power (2) outside the first pair of parenthesis:

(w^{2(2)} x^{2} y^{3(2)} )

= w^{4} x^{2} y^{6} (w^{3}x )^{3}

2. Distribute the third power (3) outside the second pair of parenthesis:

(w^{3(3)} x^{3} )

= w^{4} x^{2} y^{6} w^{9} x^{3}

3. Combine like terms:

w^{13} x^{5} y^{6}

--------------------------------------------

b) \frac{2x^{2} y^{5} }{6xy^{11} }

1. Factor the number 6 (= 2 · 3):

\frac{2x^{2} y^{5} }{2(3)xy^{11} }

2. Cancel the common factor (2):

\frac{x^{2} y^{5} }{3xy^{11} }

3. Cancel out xy^{5} in the numerator an denominator:

\frac{x}{3y^{6} }

hope this helps!

4 0
2 years ago
How much money will there be in an account at the end of 10 years if $4000 is deposited at 6% compounded quarterly
Elena L [17]

Answer:

$7,256.07

Step-by-step explanation:

A = p(1+r/n)^nt

A = 4000(1+.06/4)^(10*4)

7 0
3 years ago
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