1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zmey [24]
3 years ago
7

A time line may identify cause or effect of an event? True or False?

Computers and Technology
1 answer:
levacccp [35]3 years ago
3 0
True whenever you look at one it helps identify the cause/effect of an event
You might be interested in
The phone in your hand is a computer. So too is the machine that occupies a 100,000 square foot data center. Given their vast di
Dmitry [639]

Answer:

Well when you think about it they both do the same thing but they are diffirent, they have the same perpose but diffirent parts in them so, when you compair them the phone is smaller and slower, the bigger the computer the better it is depending on the amount of money spent on parts.

5 0
3 years ago
Design a program takes as input, X, an unsorted list of numbers, and returns the sorted list of numbers in X. The program must b
Lelechka [254]

Answer:

The program in python is as follows:

def split(X):

   L = []; G = []

   for i in range(len(X)):

       if X[i]>=X[0]:

           G.append(X[i])

       else:

           L.append(X[i])

   L.sort(); G.sort()

   return L,G

X = []

n = int(input("Length of X: "))

for i in range(n):

   inp = int(input(": "))

   X.append(inp)

   

if len(X) == 0 or len(X) == 1:

   print(X)

else:

   X1,X2=split(X)

   newList = sorted(X1 + X2)

   print(newList)

Explanation:

The following represents the split function in the previous problem

def split(X):

This initializes L and G to empty lists

   L = []; G = []

This iterates through X

   for i in range(len(X)):

All elements of X greater than 0 equal to the first element are appended to G

      <em> if X[i]>=X[0]:</em>

<em>            G.append(X[i])</em>

Others are appended to L

<em>        else:</em>

<em>            L.append(X[i])</em>

This sorts L and G

   L.sort(); G.sort()

This returns sorted lists L and G

   return L,G

The main function begins here

This initializes X

X = []

This gets the length of list X

n = int(input("Length of X: "))

This gets input for list X

<em>for i in range(n):</em>

<em>    inp = int(input(": "))</em>

<em>    X.append(inp)</em>

This prints X is X is empty of has 1 element

<em>if len(X) == 0 or len(X) == 1:</em>

<em>    print(X)</em>

If otherwise

else:

This calls the split function to split X into 2

   X1,X2=split(X)

This merges the two lists returned (sorted)

   newList = sorted(X1 + X2)

This prints the new list

   print(newList)

7 0
3 years ago
What is the most common way to perform searches in a search engine?
valina [46]
Using key words is the best way to search things in the search engine. make sure everything is spelled correctly.
5 0
3 years ago
The location on the Word screen where text will be entered is known as the _____.
mixas84 [53]
Insertion point is represented by blinking vertical line
4 0
3 years ago
Description
lapo4ka [179]

Answer:

from datetime import time, datetime, timedelta, date

for _ in iter(list, 0):

   t1 = input("Please enter time one: ")

   t2 = input("Please enter time two: ")

   if t1.isdigit() == True and (int(t1[:2])<=23 and int(t1[2:]) <= 59)\

       and t2.isdigit() == True and (int(t2[:2])<= 23 and int(t2[2:])<=59):

       time_1 = time(hour=int(t1[:2]), minute=int(t1[2:]))

       time_2 = time(hour= int(t2[:2]), minute=int(t2[2:]))

       if time_1 > time_2:

           diff = datetime. combine (date. today( ), time_1) - datetime. combine(date. today ( ), time_2)

       else:

           diff = datetime. combine (date. today( ), time_2) -datetime. combine(date. today ( ), time_1)

       diff_list = str(diff).split(":")

       del diff_list[2]

       diff_t = "". join (diff_list)

       print(diff_t)

       break        

   if t1.isdigit() == False or t2.isdigit() == False:

       print("Military Time Forest Required: Bad input, try again.")

       continue

   elif int(t1[:2])> 23 or int(t2[:2])> 23:

       print("Military Tine Format Required: Hours must be between 00 and 23, try again")

       continue

   elif int(t1[2:])> 59 or int(t2[2:])> 59:

       print("Military Tine Format Required: Minutes must be between me and 59, try again")

       continue

Explanation:

The python Datetime package is used to manipulate date and time, creating immutable Datetime objects from the various python data types like integer and string. The block of code above is a conditional for-loop statement that gets two user time value inputs and prints out the difference as a string in Military forest time format.

5 0
3 years ago
Other questions:
  • Which of the following is NOT a common GUI component? O a. Label b. Button c. Key press d. Text box
    12·2 answers
  • What is a function library?
    11·1 answer
  • Using a wireless network without the network owner's permission is known as ________.
    15·1 answer
  • What is the automotive name for the large wires that allow more electrical current to flow ?
    12·1 answer
  • How many unique ip addresses can be made in a fixed-length ip address system using 6 bits?
    8·1 answer
  • How can I change it to accepted file types: .ppt, .pptx, .xls, .xlsx, .doc, .docx, .zip, .pdf, .accdb, .msg on Inkscape?
    15·2 answers
  • Solve the following quadratic equation <br><br>y=6x^2-12x+1
    9·1 answer
  • the technique of blocking some parts of a photograph to emphasize (or draw attention to) another part of the same photograph is
    8·1 answer
  • In the event you get pulled over for a traffic stop, describe the situation from the police officer's perspective and list at le
    6·2 answers
  • ) Perform error checking for the data point entries. If any of the following errors occurs, output the appropriate error message
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!