2 years ago

Write an equation of the circle with center (2, -9) and radius 3.

Mathematics

1 answer:

KiRa [710]2 years ago

8 0

Answer:

$c = {g}^{2} + {f}^{2} + {r}^{2} \\ c = {2}^{2} + {( - 9)}^{2} + {3}^{2} \\ c = 94 \\ = > \: {x}^{2} + {y}^{2} - 4x + 18y + 94 = 0$

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A and B are supplementary angles. If A = (5x + 27)° and B = (5x – 7)º, then find the measure of angle A.

vazorg [7]

Answer:

x=16

(5x + 27)° =5(16)+27=80+27=107

(5x – 7)º= 5(16)-7=80-7=73

Step-by-step explanation

supplementary angle=180

(5x + 27)° + (5x – 7)º=180

5x+27+5x-7=180

10x+20=180

10x=180-20

10x=160

x=160/10

x=16

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(5x – 7)º= 5(16)-7=80-7=73

107+73=180

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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Kamila [148]

Answer:

17. z=39/sin45= $78/\sqrt{2}$

y=39/tan60= $39/\sqrt{3}$

x=y/sin60= $78/\sqrt{3}$

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Step-by-step explanation:

17.

because:sin45=39/z

so: z=39/sin45= $78/\sqrt{2}$

then: tan60=39/y

so: y=39/tan60= $39/\sqrt{3}$

last: sin60=y/x

so: x=y/sin60= $78/\sqrt{3}$

19.

because: tan60= $6\sqrt{3}$ /x

so: x= $6\sqrt{3}/tan60$ =6

then: sin30=x/y

so: y=x*sin30=2x=12

last: sin45=y/z

so: z=sin45*y= $\sqrt{2}y=12\sqrt{2}$

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2 years ago

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