Solve the following problems. Write the complete proof in your paper homework and for online (only) complete the probing stateme
nt (if any) that is a part of your proof or related to it.
Given: ∠CDE ≅ ∠CED, ∠A ≅ ∠B, Prove: DE ∥ AB
Given: ∠CDE ≅ ∠CED, ∠A ≅ ∠B, Prove: DE ∥ AB
1 answer:
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Let v be the speed of the slower plane in mph.
Then the speed of the faster plane will be (v + 55) mph.
the closing speed of the two planes is the sum of their speeds:
v + v + 55 = 2v + 55
Cross-multiplying, we get:
6v + 165 = 1965
6v = 1800
v = 300
The speeds of the planes are 300 mph and 355 mph.
Then the speed of the faster plane will be (v + 55) mph.
the closing speed of the two planes is the sum of their speeds:
v + v + 55 = 2v + 55
Cross-multiplying, we get:
6v + 165 = 1965
6v = 1800
v = 300
The speeds of the planes are 300 mph and 355 mph.