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2 years ago

10

Of 250 seventh grade students, 130 walk to school. What percent of seventh graders do not walk to school? % of seventh graders d

o not walk to school.

2 answers:

kvv77 [185]2 years ago

8 0

48%

48% of 250 is 120

120+130=250

Bad White [126]2 years ago

7 0

Answer:

48%

Step-by-step explanation:

I like to look at percentages as test grades. If you got a 130/250 on a test, you would simply need to view the dash line as a 'divided by'. So you would figure 130 divided by 250 is .52, or 52%... Then, you would need to subtract 52 from 100 to get 48% to get the percentage of people who do not walk to school.

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A fish-tank has a length of 27 centimeters, a width of 21 centimeters and a depth of 16 centimeters. Find the volume of the fish

NISA [10]

Answer:

To find the volume of the fish tank, we will need to multiply the height, the length, and the width of the fish tank. So, 21 x 27 x 16 = 9072 cm

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3 years ago

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Express the following as a fraction in its simplest form.

pychu [463]

Given:

Consider the given expression is:

$\dfrac{h+f}{3}+\dfrac{f+k}{2}+\dfrac{4h-k}{5}$

To find:

The simplified form of the given expression.

Solution:

We have,

$\dfrac{h+f}{3}+\dfrac{f+k}{2}+\dfrac{4h-k}{5}$

Taking LCM, we get

$=\dfrac{10(h+f)+15(f+k)+6(4h-k)}{30}$

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$=\dfrac{34h+25f+9k}{30}$

Therefore, the required simplified fraction for the given expression is $\dfrac{34h+25f+9k}{30}$ .

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2 years ago

Find the equation of the line with the giving point and slope:<br><br> (4,-3), m= -1

kondaur [170]

Y+3=-x+4
y=-x+4-3
y=-x+1

8 0

2 years ago

Someone please help??

Annette [7]

Answer:

Not 100% sure but i will say (B)

Step-by-step explanation:

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2 years ago

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Eddi Din [679]

Answer:

a) $y=\dfrac{5}{2}x$

b) yes the two lines are perpendicular

c) $y=\dfrac{5}{4}x+6$

Step-by-step explanation:

a) All this is asking if to find a line that is perpendicular to 2x + 5y = 7 AND passes through the origin.

so first we'll find the gradient(or slope) of 2x + 5y = 7, this can be done by simply rearranging this equation to the form $y = mx + c$

$5y = 7 - 2x$

$y = \dfrac{7 - 2x}{5}$

$y = \dfrac{7}{5} - \dfrac{2}{5}x$

$y = -\dfrac{2}{5}x+\dfrac{7}{5}$

this is changed into the $y = mx + c$ , and we easily see that -2/5 is in the place of m, hence $m = \frac{-2}{5}$ is the slope of the line 2x + 5y = 7.

Now, we need to find the slope of its perpendicular. We'll use:

$m_1m_2=-1$ .

here both slopes $m_1$ and $m_2$ are slopes that are perpendicular to each other, so by plugging the value -2/5 we'll find its perpendicular!

$\dfrac{-2}{5}m_2=-1$ .

$m_2=\dfrac{5}{2}$ .

Finally, we can find the equation of the line of the perpendicular using:

$(y-y_1)=m(x-x_1)$

we know that the line passes through origin(0,0) and its slope is 5/2

$(y-0)=\dfrac{5}{2}(x-0)$

$y=\dfrac{5}{2}x$ is the equation of the the line!

b) For this we need to find the slopes of both lines and see whether their product equals -1?

mathematically, we need to see whether $m_1m_2=-1$ ?

the slopes can be easily found through rearranging both equations to $y=mx+c$

Line:1

$2x + 3y =6$

$y =\dfrac{-2x+6}{3}$

$y =\dfrac{-2}{3}x+2$

Line:2

$y = \dfrac{3}{2}x + 4$

this equation is already in the form we need.

the slopes of both equations are

$m_1 = \dfrac{-2}{3}$ and $m_2 = \dfrac{3}{2}$

using

$m_1m_2=-1$

$\dfrac{-2}{3} \times \dfrac{3}{2}=-1$

$-1=-1$

since the product does equal -1, the two lines are indeed perpendicular!

c)if two perpendicular lines have the same intercept, that also means that the two lines meet at that intercept.

we can easily find the slope of the given line, y = − 4 / 5 x + 6 to be $m=\dfrac{-4}{5}$ and the y-intercept is $c=6$ the coordinate at the y-intercept will be (0,6) since this point only lies in the y-axis.

we'll first find the slope of the perpendicular using:

$m_1m_2=-1$

$\dfrac{-4}{5}m_2=-1$

$m_2=\dfrac{5}{4}$

we have all the ingredients to find the equation of the line now. i.e (0,6) and m

$(y-y_1)=m(x-x_1)$

$(y-6)=\dfrac{5}{4}(x-0)$

$y=\dfrac{5}{4}x+6$

this is the equation of the second line.

side note:

this could also have been done by simply replacing the slope(m1) of the y = − 4 / 5 x + 6 by the slope of the perpendicular(m2): y = 5 / 4 x + 6

8 0

2 years ago