Answer:
Me too not trying to get the points but how are u suppose to solve this anyway
Step-by-step explanation:
Answer:
a. ∆EGF ≅ ∆EGD
Step-by-step explanation:
Congruent triangles would have the same side lengths and the same measure of angles.
From the figure given:
EG in ∆EGF ≅ EG in ∆EGD
GF in ∆EGF ≅ GD in ∆EGD, also
EF ≅ ED.
The three angles in ∆EFG are also congruent to the three angles in ∆EGD.
Therefore, ∆EGD is congruent to ∆EGF.
∆EGF ≅ ∆EGD
The probability that it also rained that day is to be considered as the 0.30 and the same is to be considered.
<h3>
What is probability?</h3>
The extent to which an event is likely to occur, measured by the ratio of the favorable cases to the whole number of cases possible.
The probability that the temperature is lower than 80°F and it rained can be measured by determining the number at the intersection of a temperature that less than 80°F and rain.
So, This number is 0.30.
Hence, we can say that it was less than 80°F on a given day, the probability that it also rained that day is 0.30.
To learn more about the probability from the given link:
brainly.com/question/18638636
The above question is incomplete.
The conditional relative frequency table was generated using data that compared the outside temperature each day to whether it rained that day. A 4-column table with 3 rows titled weather. The first column has no label with entries 80 degrees F, less than 80 degrees F, total. The second column is labeled rain with entries 0.35, 0.3, nearly equal to 0.33. The third column is labeled no rain with entries 0.65, 0.7, nearly equal to 0.67. The fourth column is labeled total with entries 1.0, 1.0, 1.0. Given that it was less than 80 degrees F on a given day, what is the probability that it also rained that day?
#SPJ4
Answer:
a^3-125
Step-by-step explanation:
(a-5)(a^2+5a+25)
a^3+5a^2+25a-5a^2-25a-125
a^3+5a^2-5a^2+25a-25a-125
a^3-125
Answer:
The length of the actual train's car is <u>67.5 feet.</u>
Step-by-step explanation:
Given:
The scale of a model train is 1 inch to 13.5 ft.
Now, to get the length of the actual car of the train.
Let the length of actual train's car be 
And, the length of the car of model train = 
<em>According to the scale of the model train, 1 inch is equivalent to 13.5 ft. </em>
<em>Thus, 5 inches is equivalent to </em><em />
Now, to get the length of actual train's car using cross multiplication method:
By cross multiplying we get:
Therefore, the length of the actual train's car is 67.5 feet.
