We are to solve the total area of the pyramid and this can be done through area addition. We first determine the area of the base using the Heron's formula.
A = √(s)(s - a)(s - b)(s - c)
where s is the semi-perimeter
s = (a + b + c) / 2
Substituting for the base,
s = (12 + 12 + 12)/ 2 = 18
A = (√(18)(18 - 12)(18 - 12)(18 - 12) = 62.35
Then, we note that the faces are just the same, so one of these will have an area of,
s = (10 + 10 + 12) / 2 = 16
A = √(16)(16 - 12)(16 - 10)(16 - 10) = 48
Multiplying this by 3 (because there are 3 faces with these dimensions, we get 144. Finally, adding the area of the base,
total area = 144 + 62.35 = 206.35
I'm pretty sure the attachment down there can answer ur question! :D
Answer:
27
Step-by-step explanation:
If we follow the amount of players called,
Coach called three/3
Players called three/3
Three players called three/3
And make it into a equation, 1 x 3 = 3
Those three people call three more: 3 x 3 = 9
Those nine people call three more: 9 x 3 = 27
To find LCM
factor and eliminate ones already represented
1=1
2=2
3=3
4=2*2
5=5
1*2*2*3*5=60
