Whoever answers first will get brainiest!

Mathematics

2 answers:

Semenov [28]3 years ago

8 0

Possibly I believe 14

vovikov84 [41]3 years ago

7 0

Answer:

Step-by-step explanation:

We can find the value of the animal by using the first equation.

Since all 3 are the same and add up to 21, we can find the value by dividing 21 by 3:

21/3

= 7

Then, use this and the second equation to find the value of the clock:

Subtract 7 from 19:

19 - 7

= 12

Since the other two numbers are both clocks, we can find their value by dividing 12 by 2:

12/2

= 6

Then, find the value of the bowtie using the values of the clock and animal:

x + 6 + 7 = 15

x + 13 = 15

x = 2

Use these to solve the last equation. There are 2 ties, so plug in 4 because one tie is equal to the number 2.

7 + 4 x 6 = ?

7 + 24

= 31

So, the answer is 31

You might be interested in

Solve sint = cos2t, for –4π ≤ t ≤ –2π

e-lub [12.9K]

Answer:

-(23/6)π

-(19/6)π

-3π

Step-by-step explanation:

cos2t=cos^2t-sin^2t => cos^2t=1-sin^2t =>cos2t=1-2sin^2t

sint=1-2sin^2t, if x=sint, thenn we have 2x^2+x-1=0

Here x=0.5, x=-1, as x=sint => sint = -1 solutions for -4π to -2π is t=-3π,

sint = 0.5 solutions for -4π to -2π is t= -(23/6)*π, and t = -(19/6)*π

3 0

4 years ago

Graph the following sequence of transformations for

Sedbober [7]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind.

$\bf f(x)=\sqrt[3]{x}\qquad \boxed{-f(x+2)+4}\implies f(x)=\stackrel{A}{-1}\sqrt[3]{\stackrel{B}{1}x\stackrel{C}{+2}}\stackrel{D}{+4}\qquad 
\\\\\\
f(x)=-\sqrt[3]{x+2}+4$

A = -1, reflected over the x-axis

B = 1, C = 2, horizontal shift of C/B or 2, to the left.

D = 4, shifted upwards by 4 units.

check the picture below.