Given:
m∠B = 44°
Let's find the following measures:
m∠A, m∠BCD, m∠CDE
We have:
• m∠A:
Angle A and Angle B are interior angles on same side of a transversal.
The interior angles are supplementary.
Supplementary angles sum up to 180 degrees
Therefore, we have:
m∠A + m∠B = 180
m∠A + 44 = 180
Subtract 44 from both sides:
m∠A + 44 - 44 = 180 - 44
m∠A = 136°
• m,∠,BCD:
m∠BCD = m∠A
Thus, we have:
m∠BCD = 136°
• m∠CDE:
Angle C and angle CDE form a linear pair.
Linear pair of angles are supplementary and supplementary angle sum up to 180 degrees.
Thus, we have:
m∠D = m∠B
m∠D = 44°
m∠CDE + m∠D = 180
m∠CDE + 44 = 180
Subract 44 from both sides:
m∠CDE + 44 - 44 = 180 - 44
m∠CDE = 136°
ANSWER:
• m∠A = 136°
,
•
,
• m∠BCD = 136°
,
•
,
• m∠CDE = 136°
Answer:
B. 2(-3w+(-11)
Step-by-step explanation:
-3(2w+6)-4=
-6w-18-4=
-6w-22=
2(-3w+(-11)
Answer is provided in the image attached.
<span>These triangles are impossible:
a triangle with sides of 3 inches, 4 inches, and 8 inches
(the longest side is greater than the sum of the other 2 sides)
an obtuse equilateral triangle
(all angles in an </span><span>equilateral triangle are acute)
</span>
<span>a triangle with two right angles
The angles of ALL triangles must sum exactly to 180 degrees. Two right angles sum to 180 degrees so the third angle would have to be zero degrees.
</span>
Answer:
hindi sulotion kung hindi man sorry nalang
walarin akong alam diyaan
Step-by-step explanation:
im sosory
