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Ierofanga [76]
3 years ago
13

What is 40/17 rounded to the nearrst hundreth as a decimal ​

Mathematics
2 answers:
vaieri [72.5K]3 years ago
7 0
40 over 17 should be correct and can I get marked brainless
STatiana [176]3 years ago
4 0

Answer:

★ 40 over 17 is roughly 2.35294, which can be rounded to the nearest hundredth as 2.35

Step-by-step explanation:

Hope you have a great day :)

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A tank with capactity 500 gal originally contains 200 gal water with 100 lbs of salt mixed into it. Water containing 1 lb of sal
prisoha [69]

Answer:

The amount of salt in the tank at any moment t is

           f(t)=-\frac {4\times 10^6}{(200+t)^2}+200+t

The concentration of salt in the tank when it is at the point of overflowing is 0.968.

The theoretical limiting concentration of an infinite tank is 1 lb per gallon.

Step-by-step explanation:

Let f(t) be the amount of salt in the tank at any time t.

Then, its time rate of change, f'(t),  by (balance law).

Since three gallons of salt water runs in the tank per minute, containing 1lb of salt, the salt rate is

                               3.1=3

The amount of water in the tank at any time t is.

                           200+(3-2)t=200+t,

Now, the outflow is 2 gal of the solution in a minute. That is \frac 2{200+t} of the total solution content in the tank, hence \frac 2{200+t} of the salt salt content f(t), that is \frac{2f(t)}{200+t}.

Initially, the tank contains 100 lb of salt,

Therefore we obtain the initial condition   f(0)=100

Thus, the model is

                       f'(t)=3-\frac{2f(t)}{200+t}, f(0)=100

                \Rightarrow f'(t)+\frac{2}{200+t}f(t)=3, f(0)=100

                      p(t)=\frac{2}{200+t} \;\;\text{and} \;\;q(t)=3   Linear ODE.

 so, an integrating factor is

                 e^{\int p dt}=e^{2\int \frac{dt}{200+t}=e^{\ln(200+t)^2}=(200+t)^2

and the general solution is

               f(t)(200+t)^2=\int q(200+t)^2 dt+c

            \Rightarrow f(t)=\frac 1{(200+t)^2}\int 3(200+t)^2 dt+c

           \Rightarrow f(t)=\frac c{(200+t)^2}+200+t

Now using the initial condition and find the value of c.

   100=f(0)=\frac c{(200+0)^2}+200+0\Rightarrow -100=\frac c{200^2}

                                                  \Rightarrow c=-4000000=-4\times 10^6

            \Rightarrow f(t)=-\frac {4\times 10^6}{(200+t)^2}+200+t

is the amount of salt in the tank at any moment t.

Initially, the tank contains 200 gal of water and the capacity of the tank is 500 gal. This means that there is enough place for

                                 500-200=300 gal

of water in the tank at the beginning. As concluded previously, we have one new gal in the tank at every minute. hence the tank will be full in 30min.

Therefore, we need to calculate f(300) to find the amount of salt any time prior to the moment when the solution begins to overflow.

       f(300)=-\frac{4\times 10^6}{(200+300)^2}+200+300=-16+500=484

To find the concentration of salt at that moment, divide the amount of salt with the amount of water in the tank at that moment, which is 500L.

               \text{concentration at t}=300=\frac{484}{500}=0.968

If the tank had an infinite capacity, then the concentration would be

              \lim\limits_{t \to \infty} \frac{f(t)}{200+t}=  \lim\limits_{t \to \infty}\left(\frac{\frac{3\cdot 10^6}{(200+t)^2}+(200+t)}{200+t}\right)

                              = \lim\limits_{t \to \infty} \left(\frac{4\cdot 10^6}{(200+t)^3}+1\right)

                               =1

Hence, the theoretical limiting concentration of an infinite tank is 1 lb per gallon.

     

3 0
4 years ago
The graph of a function f crosses the x-axis at -1 and 3 and touches the x-axis at 5. Which equations could define this function
sattari [20]

Given:

The points where the graph crosses the <em>x</em>-axis are -1 and 3.

The point where the graph touches the <em>x</em>-axis is at 5.

The objective is to find the correct equation of the function.

Explanation:

The equation representing the point <em>x</em> = -1, crossing the <em>x</em>-axis can be represented as,

\begin{gathered} x=-1 \\ (x+1)=0_{} \end{gathered}

Similarly, the equation representing the point <em>x</em> = 3, crossing the <em>x</em>-axis can be represented as,

\begin{gathered} x=3 \\ (x-3)=0 \end{gathered}

Similarly, the equation representing the point <em>x</em> = 5, touching the <em>x</em>-axis can be represented as,

\begin{gathered} x=5,x=5 \\ (x-5)(x-5)=0 \\ (x-5)^2=0 \end{gathered}

By combining all the equations of the graph, the function can be represented as,

f(x)=(x+1)(x-3)(x-5)^2

Hence, option (B) is the correct answer.

5 0
1 year ago
Write an equation that expresses the following relationship.
Gnesinka [82]

Answer:

p = k(d)/u^2

Step-by-step explanation:

<em>BRAINLIEST, PLEASE!</em>

7 0
3 years ago
Pre-calculus Help Please! Express the complex number in trigonometric form.
lana66690 [7]
We have that

 3 = 3 + 0i -----------> rewrite as 3(1 + 0i) 

<span>So now what we have to do is figure out which of the above expressions has cos a = 1 and sin a = 0. </span>
<span>cos 0 = 1, and sin 0 = 0, so that's the answer that we want. 

</span><span>the answer is: </span>
3 = 3(cos 0 + i sin 0)
3 0
4 years ago
3(a - 4) ≤ 33<br> Help me solve
yaroslaw [1]

Answer:

a ≤ 15

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

3(a - 4) ≤ 33

<u>Step 2: Solve for </u><em><u>a</u></em>

  1. Divide 3 on both sides:                    a - 4 ≤ 11
  2. Add 4 on both sides:                        a ≤ 15

Here we see that any value <em>a </em>less than or equal to 15 would work as a solution to the inequality.

3 0
3 years ago
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