How do the number of faces, vertices, and edges of a cube compare to the number of faces, vertices, and edges of a tetrahedron?
A cube has more faces than a tetrahedron. A cube has more vertices than a tetrahedron. A cube has more edges than a tetrahedron.
1 answer:
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Answer: 17 -3n
Explanation:
In the given arithmetic progression 20,17,14,11,8....
first term that is a = 20
common difference that is d= a2-a1 = 17-20 = -3
let n is the nth term
= a+(n-1)d
substituting the values of first, common,difference and n
=20+(n-1) (-3)
= 20 -3n+3
=23 -3n