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ANTONII [103]
3 years ago
13

Jon thinks of a number between 1 and 10.The cube of the number is equal to the square of double the number.What is number jon is

thinking of?​
Mathematics
2 answers:
siniylev [52]3 years ago
6 0

Answer:

4

Step-by-step explanation:

4^2=8 8^2=64

4^3=64

murzikaleks [220]3 years ago
5 0
Jon is thinking about 4
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2x^{2}-5x-5=0

Step-by-step explanation:

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If something starts out costing $500, and then is marked down by 25% on each of three separate occasions,what is the final price
astra-53 [7]
First markdown:  0.75($500) = $375
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3 0
3 years ago
I NEED THIS ASAP, PLEASE HELP!!!
WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

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B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

137 / 2 = 68.5

IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

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7 0
3 years ago
PLEASE HELP, THIS ONE IS EVEN MORE CONFUSING THAN THE OTHER ONE I ASKED xDDD
labwork [276]
It should be the 3rd one but idk for sure. if its not then its the 3rd one
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