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2 years ago

What is a common dominator for 5/6+1/6

Mathematics

2 answers:

ValentinkaMS [17]2 years ago

8 0

Answer:

The least common denominator for 5/6 and 1/6 is 6, and if you wanted the equation solved then it would be 5/6+1/6 which equals 1.

Hope this helps, have a good day/night and stay safe! :)

german2 years ago

4 0

Answer:

Step-by-step explanation:

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3 years ago

Using the quadratic formula to solve x2 + 20 = 2x, what are the values of x?

jeka94

by Quadratic formula , $x^2 + 20 = 2x$ , values of x are $x = 1 \pm (1)i\sqrt{19}}$ . None of mentioned options are correct according to question!

<u>Step-by-step explanation:</u>

Here we have , expression x2 + 20 = 2x or , $x^2 + 20 = 2x$ .

We know that Quadratic formula is :

$x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$

$x^2 + 20 = 2x$

⇒ $x^2-2x+20=0$

$a=1\\b=-2\\c=20$

Putting this value in equation $x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$ :

⇒ $x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$

⇒ $x = \frac{-(-2) \pm \sqrt{(-2)^{2}-4(1)(20)}}{2(1)}$

⇒ $x = \frac{2 \pm \sqrt{4-80}}{2}$

⇒ $x = (\frac{2 \pm 2i\sqrt{19}}{2})$

⇒ $x = 1 \pm (1)i\sqrt{19}}$

Therefore , by Quadratic formula , $x^2 + 20 = 2x$ , values of x are $x = 1 \pm (1)i\sqrt{19}}$ . None of mentioned options are correct according to question!

7 0

3 years ago

(x^2 - x^(1/2))/(1-x^(1/2))

Levart [38]

$\frac { \left( { x }^{ 2 }-{ x }^{ \frac { 1 }{ 2 } } \right) }{ \left( 1-{ x }^{ \frac { 1 }{ 2 } } \right) }$

$\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x } \right) }{ \left( 1-\sqrt { x } \right) } \cdot 1$

$\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x } \right) }{ \left( 1-\sqrt { x } \right) } \cdot \frac { \left( 1+\sqrt { x } \right) }{ \left( 1+\sqrt { x } \right) }$

$\\ \\ =\frac { { x }^{ 2 }+{ x }^{ 2 }\sqrt { x } -\sqrt { x } -x }{ 1+\sqrt { x } -\sqrt { x } -x }$

$\\ \\ =\frac { -\sqrt { x } \left( 1-{ x }^{ 2 } \right) -x\left( 1-x \right) }{ \left( 1-x \right) }$

$\\ \\ =\frac { -\sqrt { x } \left( 1+x \right) \left( 1-x \right) -x\left( 1-x \right) }{ \left( 1-x \right) }$

$\\ \\ =\frac { \left( 1-x \right) \left\{ -\sqrt { x } \left( 1+x \right) -x \right\} }{ \left( 1-x \right) }$

$\\ \\ =-\sqrt { x } \left( 1+x \right) -x\\ \\ =-{ x }^{ \frac { 1 }{ 2 } }\left( 1+{ x }^{ \frac { 2 }{ 2 } } \right) -x$

$\\ \\ =-{ x }^{ \frac { 1 }{ 2 } }-{ x }^{ \frac { 3 }{ 2 } }-x\\ \\ =-\sqrt { x } -\sqrt { { x }^{ 3 } } -x$

3 0

3 years ago

Read 2 more answers

Does anyone know this?

Margarita [4]

Answer:

[-8, 7]

Step-by-step explanation:

The range is the set of values used for the y-coordinates of the all the points of the function.

The highest value of the function is at point (8, 7), so the greatest value y has is 7.

The lowest point of the function is at point (-3, -8), so the least value of y is -8.

Range: [-8, 7]

5 0

3 years ago

Read 2 more answers

Eva is making a pattern using these shapes can you arrange Evas shapes to make a symmetrical pattern

ratelena [41]

Answer:

pyramid, cone, sphere, cube

Step-by-step explanation:

A symmetrical pattern is one that is arranged in such a way that there is a progressive repetition of a pattern. Each pattern formed is the same with respect to each other.

Eva could form series symmetrical patterns with the shapes he has, which depends on the arrangement of the shapes to form desired pattern.

One simple pattern to be formed is;

pyramid, cone, sphere, cube

pyramid, cone, sphere, cube.

Thus, this would generate four symmetrical continuous patterns.

pyramid, cone, sphere, cube : pyramid, cone, sphere, cube : pyramid, cone, sphere, cube : pyramid, cone, sphere, cube.

6 0

3 years ago