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Ahat [919]
3 years ago
10

Need GF near waco,texas. Question =You want my # or snap?

Mathematics
1 answer:
alukav5142 [94]3 years ago
7 0

Answer:

im not even close  but nice

Step-by-step explanation:

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Miguel wants to bike a total of 100 miles over the course of one week in the summer. He logs how much he bikes each day in the t
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Change all of the number into the same form for ease of adding.

16.3 + 14.5 + 18.75 + 12.25 + 22.6 = 84.4

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Miguel has to ride a total of 15.6 miles on Saturday and Sunday

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What cryptographic method, first proposed in the mid-1980s, makes use of sloping curves instead of large prime numbers?
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3 years ago
An automobile manufacturer claims that its van has a 31.3 miles/gallon (MPG) rating. An independent testing firm has been contra
Yuliya22 [10]

Answer:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z=\frac{31.1-31.3}{\frac{1.3}{\sqrt{140}}}=-1.82  

p_v =2*P(z  

If we compare the p value and the significance level given \alpha=0.02 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is NOT significantly different from 31.3 at 2% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=31.1 represent the sample mean

\sigma=1.3 represent the population standard deviation for the sample  

n=140 sample size  

\mu_o =31.3 represent the value that we want to test  

\alpha=0.02 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We can assume that we conduct a hypothesis in order to check if the true mean is equal to 31.3 , the system of hypothesis would be:  

Null hypothesis:\mu =31.3  

Alternative hypothesis:\mu \neq 31.3  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{31.1-31.3}{\frac{1.3}{\sqrt{140}}}=-1.82  

P-value  

Since is a two-sided test the p value would be:  

p_v =2*P(z  

Conclusion  

If we compare the p value and the significance level given \alpha=0.02 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is NOT significantly different from 31.3 at 2% of signficance.  

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Teresa wrote this expression to describe the total distance she was going to swim during two swim classes.
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