3 is incorrect, should be 28.9
16^2 + 18^2 = EG^2
256 + 324
580 = EG^2
EG ≈ 24.08
16^2 + 24.08^2 = AG^2
256 + 580 = AG^2
836 = AG^2
AG ≈ 28.9
5 is incorrect:
The base is 8.
Draw an altitude the base.
Since the triangle is isoceles, it divides the base in half.
Half of that base is 4.
Two right triangles have been formed with one leg 4 and hypotenuse 8.
4^2 + b^2 = 8^2
16 + b^2 = 64
b^2 = 48
b ≈ 6.93
The height of the triangle is 6.93, the base is 8.
A = bh/2 = 8*6.93/2 ≈ 27.7 ≈ 28
Answer:
C
Step-by-step explanation:
because the solution dors not include -3 but everything less than.
Answer:
D
Step-by-step explanation:
sohcahtoa
Sin x = 32/58
sin x = .5517
x = 33°
Area is base x height divide by 2
6x13=78
78 divide by 2 is 39
I encountered this problem before but it had an accompanying image and list of answer choices.
I'll attach the image and include the list of options.
Each unit on the grid stands for one mile. Determine two ways to calculate the distance from Josie's house to Annie's house.
A) Distance Formula and Slope Formula
B) Midpoint Formula and Slope Formula
C) Distance Formula and Midpoint Formula
<span>D) Distance Formula and Pythagorean Theorem
</span>
My answer is: D.) Distance formula and Pythagorean Theorem.
When looking at the image, I can visualize a right triangle. I'll simply get the measure of the long and short legs and solve for the hypotenuse.
Since the distance formula is derived from the Pythagorean theorem, it can be used to determine the distance from Josie's house to Annie's house.