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harina [27]
2 years ago
14

What is the name of the polynomial, 3x³ +2x + 4?

Mathematics
1 answer:
vekshin12 years ago
3 0

Answer:

cubic trinomial

Step-by-step explanation:

can I have brainllest

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Will at walnut float or sink in water
Kipish [7]
It will float.. Sorry if i am wrong
4 0
3 years ago
Plzz helppp it's due today​
juin [17]

Answer:

8

Step-by-step explanation:

use trig functions

2 sides and 1 angle given

Sides given

  • hypotenuse -> x
  • opposite side to 30˚ -> 4

Angle

  • 30˚

trig function associated with hyp and opp is sin

sin(x) = opp/hyp

substitute

sin 30˚ = 4/x

solve for x

0.5 = 4/x

0.5x = 4

x = 8

7 0
3 years ago
Read 2 more answers
Nth term of 4,1,-2,-5,-8
suter [353]
In the sequence, the numbers are going down by -3. So the nth term must start with -3n. To get from -3 to 4 you must add 7. This makes the nth term -3n+7.
4 0
3 years ago
Read 2 more answers
Line segment JM has endpoints with coordinates 0 and 25 on a number line. Points K and L are on segment JM. K has a coordinate o
Pepsi [2]

Answer:

  • D. 216/625

Step-by-step explanation:

  • The length of the segment JM is 25 units.
  • The segment JL is between 0 and 12, so is 12 units.
  • The segment KL is between 5 and 12, so is 7 units.

<u>The probabilities for each point:</u>

  • P(point on JL) = 12/25
  • P(point not on KL) = 1 -  7/25 = 18/25

<u>Required probability:</u>

  • P = 12/25*18/25 = 216/625

Correct choice is D

5 0
3 years ago
A = √7 + √c and b = √63 + √d where c and d are positive integers.
mrs_skeptik [129]

Answer:

\displaystyle a:b=\frac{1}{3}

Step-by-step explanation:

<u>Ratios </u>

We are given the following relations:

a=\sqrt{7}+\sqrt{c}\qquad \qquad[1]

b=\sqrt{63}+\sqrt{d}\qquad \qquad[2]

\displaystyle \frac{c}{d}=\frac{1}{9} \qquad \qquad [3]

From [3]:

9c=d

Replacing into [2]:

b=\sqrt{63}+\sqrt{9c}

We can express 63=9*7:

b=\sqrt{9*7}+\sqrt{9c}

Taking the square root of 9:

b=3\sqrt{7}+3\sqrt{c}

Factoring:

b=3(\sqrt{7}+\sqrt{c})

Find the ration a:b:

\displaystyle a:b=\frac{\sqrt{7}+\sqrt{c}}{3(\sqrt{7}+\sqrt{c})}

Simplifying:

\boxed{a:b=\frac{1}{3}}

3 0
3 years ago
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