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babymother [125]
2 years ago
9

What is the range for the following set of data?

Mathematics
2 answers:
ankoles [38]2 years ago
7 0
I think the answer would be D
PolarNik [594]2 years ago
6 0

Answer:

The answer would be D 10

Step-by-step explanation:

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What is the equation of the line that passes through (–2, 3) and is parallel to 2x + 3y = 6?
sergeinik [125]
If they are parallel then the coefficients of x and y will remain the same.  Only the constant will change.

2x + 3y = ?
2(-2) +3(3) = -4 + 9 = 5 so ? is 5

ANSWER: 2x + 3y = 5
6 0
3 years ago
Sunday elementary school is having its annual Read a thon. the third graders have read 573 books so fair. Their goal is to read
il63 [147K]
The answer would be 901 because they said what is the least number they would need to read and their goal is MORE than 900. The amount of books that they already had is useless information (Ignore). They love giving trick questions. :)
4 0
3 years ago
The sum of a number x and -7 is less than or equal to 18.
pishuonlain [190]

Step-by-step explanation:

x + (-7) ≤ 18

x - 7 ≤ 18

x ≤ 18 + 7

x ≤ 25

Value of x is less than or equal to 25

5 0
3 years ago
Lara is a 50% partner. She is guaranteed payment of no less than 20,000. The partnership's income before deducting guaranteed pa
enyata [817]

Answer:

Lara's share = 25000

Step-by-step explanation:

Partnership's income = 50,000

Lara's guaranteed payment = 20,000

As the Income 50,000 is larger than Lara's guaranteed payment i.e 20,000. Since Lara is 50% partner so she will receive half the amount of the partnership's income.

Partnership's Income = 50,000  

Half of Partnership's income = 50,000/2

                                                = 25,000

Therefore, Lara's distributive share is 25,000.

!!

8 0
3 years ago
Suppose that five ones and four zeros are arranged around a circle. Between any two equal bits you insert a 0 and between any tw
PolarNik [594]

Answer:

Using <u>backward reasoning</u> we want to show that <em>"We can never get nine 0's"</em>.

Step-by-step explanation:

Basically in order to create nine 0's, the previous step had to have all 0's or all 1's. There is no other way possible, because between any two equal bits you insert a 0.

If we consider two cases for the second-to-last step:

<u>There were 9 </u><u>0's</u><u>:</u>

We obtain nine 0's if all bits in the previous step were the same, thus all bit were 0's or all bits were 1's. If the previous step contained all 0's, then we have the same case as the current iteration step. Since initially the circle did not contain only 0's, the circle had to contain something else than only 0's at some point and thus there exists a point where the circle contained only 1's.

<u>There were 9 </u><u>1's</u><u>:</u>

A circle contains only 1's, if every pair of the consecutive nine digits is different. However this is impossible, because there are five 1's and four 0's (we have an odd number of bits!), thus if the 1's and 0's alternate, then we obtain that 1's that will be next to each other (which would result in a 1 in the next step). Thus, we obtained a contradiction and thus assumption that the circle contains nine 0's after iteratins the procedure is false. This then means that you can never get nine 0's.

To summarize, in order to create nine 0's, the previous step had to have all 0's or al 1's. As we didn't start the arrange with all 0's, the only way is having all 1's, but having all 1's will not be possible in our case since we have an odd number of bits.

<u />

5 0
3 years ago
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