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tankabanditka [31]

2 years ago

6

Please help me with this

1 answer:

Anni [7]2 years ago

6 0

Sub in the numbers for x

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Need help asap the graphs below have the same shape. what is the equation of the red graph?

exis [7]

Answer:

The highlighted one is correct

B F(x) = 2 - x²

Step-by-step explanation:

3 0

2 years ago

Where are the asymptotes for the following function located? f(x)= 7/ x^2-2x-24

Zarrin [17]

Factor the demoniator:-

x^2 -2x - 24 = (x - 6)(x + 4)

the asymptotes occurs when denominator = 0

so here they are the vertical lines x = 6 and x = -4

7 0

2 years ago

Read 2 more answers

Give the properties for the equation -2x 2 - y + 10x - 7 = 0.

Sladkaya [172]

Given:

The quadratic equation is

$-2x^2-y+10x-7=0$

To find:

The vertex of the given quadratic equation.

Solution:

If a quadratic function is $f(x)=ax^2+bx+c$ , then

$Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)$

We have,

$-2x^2-y+10x-7=0$

It can be written as

$-2x^2+10x-7=y$

$y=-2x^2+10x-7$ ...(i)

Here, $a=-2,b=10,c=-7$ .

$\dfrac{-b}{2a}=\dfrac{-10}{2(-2)}$

$\dfrac{-b}{2a}=\dfrac{-10}{-4}$

$\dfrac{-b}{2a}=\dfrac{5}{2}$

Putting $x=\dfrac{5}{2}$ in (i), we get

$y=-2(\dfrac{5}{2})^2+10(\dfrac{5}{2})-7$

$y=-2(\dfrac{25}{4})+\dfrac{50}{2}-7$

$y=\dfrac{-50}{4}+25-7$

$y=\dfrac{-25}{2}+18$

On further simplification, we get

$y=\dfrac{-25+36}{2}$

$y=\dfrac{11}{2}$

So, the vertex of the given quadratic equation is $\left(\dfrac{5}{2},\dfrac{11}{2}\right)$ .

Therefore, the correct option is A.

3 0

2 years ago

8,minus some number divided by 3, equals 6. find the numbers

algol [13]

8 - (-10) = 18
18 / 3 = 6
hope this helps

5 0

2 years ago

What is the completely factored form of f(x) = x^3-7x^2 2x +4?

Roman55 [17]

The answer is (x-1) (x^2-6x-4)

5 0

2 years ago