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slega [8]
3 years ago
10

How is perimeter measured?

Mathematics
1 answer:
vazorg [7]3 years ago
6 0

Perimeter is the linear distance around an object.

It is measured in c) linear units

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What is 2/5 divided by -1/2 minus 3/2
shutvik [7]

Answer:

-  \frac{23}{10}

Step-by-step explanation:

\frac{2}{5}  \div  \frac{ - 1}{2}  -  \frac{3}{2}

➡️ -  \frac{2}{5}  \times 2 -  \frac{3}{2}

➡️ -  \frac{4}{5}  -  \frac{3}{2}

➡️ -  \frac{23}{10}

5 0
3 years ago
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Find the 11th term of the following geometric sequence.<br><br> 1,5, 25, 125, ...
salantis [7]

Answer:

9,765,625

Step-by-step explanation:

7 0
3 years ago
The range of the data: 7, 10, 30, 16, 8, 5, 3, 18, 35, and 1 tell the answer only
Nikitich [7]
It is 32 because highest number subtracted by lowest
3 0
3 years ago
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If x^2+1/x^2=3 find the value of x^2/(x^2+1)^2<br> Express answer as a common fraction.<br> Thanks!!
timama [110]

x^2+\dfrac1{x^2}=3\implies x^4+1=3x^2\implies x^4-3x^2+1=0

By the quadratic formula,

x^2=\dfrac{3\pm\sqrt5}2\implies x^2+1=\dfrac{5\pm\sqrt5}2

Then

(x^2+1)^2=\dfrac{25\pm10\sqrt5+5}4=\dfrac{15\pm5\sqrt5}2

\implies\dfrac{x^2}{(x^2+1)^2}=\dfrac{\frac{3\pm\sqrt5}2}{\frac{15\pm5\sqrt5}2}=\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}

Multiply numerator and denominator by the denominator's conjugate:

\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}\cdot\dfrac{15\mp5\sqrt5}{15\mp5\sqrt5}=\dfrac{45\pm15\sqrt5\mp15\sqrt5-25}{15^2-(5\sqrt5)^2}=\dfrac{20}{100}=\dfrac15

3 0
3 years ago
Find the quotient.<br>8.24 = 1.7=​
WITCHER [35]

Answer:

4.847

Step-by-step explanation:

divide 8.24 by 1.7

8.24 /1.7 = 4.847

6 0
4 years ago
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