Find the greatest common factor. In this case it is 3. Divide each group by 3.
15÷3=5 quarters
30÷3=10 dimes
48÷3=16 nickels
Next count them by the coin's value:
5 × 0.25 = $1.25
10 × 0.10 = $1
16 × 0.05 = $0.80
Add them up:
= $3.05 in each group and there are three groups.
So, the greatest number of groups that he can make is 3; there will be 5 quarters, 10 dimes, and 16 nickels in each group, which is worth $3.05 in each group.
Answer:
8.27
Step-by-step explanation:
subtracting a negative number creates a positive
two negatives = a positive
Answer:
Problem 1. <em>(19/2)b + 15</em>
Problem 2. <em>3/16</em>
Step-by-step explanation:
Question number 1
5/8 (16b+24) -1/2b =
= (5/8) * (16/1) * b + (5/8) * 24 - (1/2)b
= 10b + 15 - (1/2)b
= (20/2)b - (1/2)b + 15
= (19/2)b + 15
Question number 2
3/4 (16/64 + 12a) -9a =
= (3/4) * (16/64) + (3/4) * 12a - 9a
= (3 * 16)(4 * 64) + (3/4) * (12/1) * a - 9a
= (3 * 1)(4 * 4) + (3 * 12)/(4 * 1) * a - 9a
= 3/16 + (3 * 3)/(1 * 1) * a - 9a
= 3/16 + 9a - 9a
= 3/16
Answer:
Ok, we know that we can write a horizontal translation as:
y' = f(x - A)
where if A is positive, this moves the graph of f(x) A units to the right.
Why is this?
Ok, let's compare:
y = f(x)
and
y' = f(x - A)
in y, when x = 0 we have f(0).
While to have this same point in y', we need to evaluate in x = A.
f(A - A) = f(0).
Then the value f(0) is now at x = A, this means that the point moved A units to the right.
And you can do this for all the values, so you will find that the entire graph of f(x) has ben moved A units to the right.
