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GrogVix [38]
3 years ago
12

Find x and IJ is HK is an altitude of triangle HIJ

Mathematics
1 answer:
ss7ja [257]3 years ago
4 0
3x+3=90
subtract 3 from both sides
3x=87
divide both sides by 3
x=29

To find IJ, plug in the x value
x+8+x-9
29+8+29-9
57=IJ
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Suppose a figure is located in Quadrant I. Which of the following sequences will result in an image that is located in Quadrant
lesantik [10]

Answer:

So option b is right.

Step-by-step explanation:

Given that a figure is located in Quadrant I.

The figure is transformed and the image is located in quadrant iv.

We have to select the option which would have resulted in this.

A) rotating 360 degrees would result in the same place i.e. I quadrant hence wrong.

B) rotating 180 degrees counterclockwise, will make y coordinate negative but x coordinate will remain as it is.

Hence we get image in the IV quadrant.

THis option is correct

C) Rotating90 degrees counterclockwise will not transform all the coordinates to the IV quadrant hence wrong

D) Rotating 270 degrees counterclockwise would make the image in III quadrant hence wrong

So option b is right.

5 0
3 years ago
5x-3-2x/7=24 solve for x
bearhunter [10]

Answer:

X=5.7

Step-by-step explanation:

5x-3-2x/7=24

We simplify the equation to the form, which is simple to understand  

5x-3-2x/7=24

Simplifying:

5x-3-0.285714285714x=24

We move all terms containing x to the left and all other terms to the right.  

+5x-0.285714285714x=+24+3

We simplify left and right side of the equation.  

+4.71428571429x=+27

We divide both sides of the equation by 4.71428571429 to get x.  

x=5.72727272727

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Rainbow [258]

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3 years ago
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Find the value of tanθ, if cosθ = 4/5 ; 0° ≤ θ< 90°
Montano1993 [528]

Answer:

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Step-by-step explanation:

<u>Given </u>

  • cosθ = 4/5
  • 0° ≤ θ < 90°

<u>In the first quadrant both sine and cosine are positive, so as tangent.</u>

  • tanθ = sinθ / cosθ =
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  • \sqrt{1 - (4/5)^2} / 4/5 =
  • \sqrt{9/25} / 4/5 =
  • 3/5*5/4 =
  • 3/4
4 0
3 years ago
Which of the following appear in the diagram below? Check all that apply. X Z. W O A. _XYZ B. ZYXZ C. w D. YX​
iren2701 [21]

Answer:

A, C, and D.

Step-by-step explanation:

<XYZ appears in the diagram as the vertex angle Y, has two sides, YW and YX that intersect at point Y to form <XYZ.

Thus, <XYZ, line segments YW and YX all appear in the diagram given.

<YXZ does not appear because there's no vertex angle labelled X.

8 0
3 years ago
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