The complete factorisation of the polynomial given; x³ + 2x² + 4x + 8 as in the task content can be factorised and determined as; Choice D; (x+2)(x+2i)(x-2i).
<h3>What is the complete factorisation of the given polynomial; x³ + 2x² + 4x+8?</h3>
It follows from the given task content that the polynomial whose factors are to be determined by means of factorisation is; x³ + 2x² + 4x+8.
It follows from observation that one of the zeros of the polynomial expression is at; x = -2.
Consequently, one of the factors of the polynomial in discuss is; (x+2).
x³ + 2x² + 4x+8 = (x+2) (x² - 4i²)
= (x+2)(x+2i)(x-2i)
Consequently, it follows that the complete factorisation of the polynomial is; (x+2)(x+2i)(x-2i).
Read more on polynomial factorisation;
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(This is the order in terms with the rule) 5 ... 8 ... 11 ... 14 ... 17 ... 20 ... 23 ... 26 ... 29 ... 32 ... So victor should say the number 32
Hello here is a solution :
f'(x) =( sin11x)'cos11x +<span>sin11x(cos11x)'
(sin(ax+b))'=a cos(ax+b)
</span>(cos(ax+b))'=-a sin(ax+b)
f'(x) = 11 cos11xcos11x-11sin11xsin11x
f'(x) = 11(cos11x)²-11(sin11x)²
It is 7 thousand and a bunch of random numbers
X is a variable, a variable you have to divide to cancel out
