Building a is 190 feet shorter than building

1 answer:

3 0

We will solve this using a system of equations. The first part tells us that building a is 190 feet shorter than building b. Our first equation, then, is b=190+a. The second part tells us that the addition of the two buildings' heights is 1480. So our second equation is a + b = 1480. The first equation is already solved for b, so let's sub that value into the second equation for b: a+(190+a)=1480. 2a + 190 = 1480 and 2a = 1290. That means that building a is 645 feet tall. Building b is 190 feet taller, so b = 190 + 645, which is 835.

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The rectangle has an area….

Anon25 [30]

Answer:

5.5193237 times 10 to the power of -10

Step-by-step explanation:

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A total of 243 tickets were sold for the school play. They were either adult tickets or student tickets. The number of student t

alina1380 [7]

Answer:

81 adult tickets

Step-by-step explanation:

Step 1:

Set up a system of equations

Since the adult tickets and student tickets add to 243, we can do

$a+s=243$

and the student tickets sold were 2x the adult tickets, we can do

$s=2a$

We can replace s in the first equation adding to 243 with 2a

$a+s(2a)=243\\3a=243\\$

Step 2:

Solve for a. We can divide both sides by 3.

$a=81$

Therefore, there were 81 adult tickets sold.

Step 3:

We can check our work! Since we learned earlier the student tickets are 2x adult tickets, we can multiply 81 by 2 and add that to 81 to see if it equals 243!

$s=2a\\s=2(81)\\s=162$