Answer:
OPTION A: ![$ \frac{1}{2^{15}} $](https://tex.z-dn.net/?f=%24%20%5Cfrac%7B1%7D%7B2%5E%7B15%7D%7D%20%24)
Step-by-step explanation:
We should know that:
![$ (a^b)^c = a^{b . c} $](https://tex.z-dn.net/?f=%24%20%28a%5Eb%29%5Ec%20%3D%20a%5E%7Bb%20.%20c%7D%20%24)
So, ![$ (2^3)^{-5} = 2^{3 . (-5)}} $](https://tex.z-dn.net/?f=%24%20%282%5E3%29%5E%7B-5%7D%20%3D%202%5E%7B3%20.%20%28-5%29%7D%7D%20%24)
![$ = 2^{-15} $](https://tex.z-dn.net/?f=%24%20%3D%202%5E%7B-15%7D%20%24)
This is equivalent to ![$ \frac{1}{2^{15}} $](https://tex.z-dn.net/?f=%24%20%5Cfrac%7B1%7D%7B2%5E%7B15%7D%7D%20%24)
Hence, OPTION A is the answer.
Answer:
x=1 if I understood correctly.
Step-by-step explanation:
![\sqrt{x} + 5 + x - 3 = 4](https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%7D%20%20%2B%205%20%2B%20x%20-%203%20%3D%204)
![\sqrt{x} + 2 + x = 4](https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%7D%20%20%2B%202%20%2B%20x%20%3D%204)
![\sqrt{x} + x = 2](https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%7D%20%20%2B%20x%20%3D%202)
At this point if you try all the integers, you will find that only 1 is the solution to this equation, because:
![\sqrt{1} + 1 = 2](https://tex.z-dn.net/?f=%20%5Csqrt%7B1%7D%20%20%2B%201%20%3D%202)
![1 + 1 = 2](https://tex.z-dn.net/?f=1%20%2B%201%20%3D%202)
![2 = 2](https://tex.z-dn.net/?f=2%20%3D%202)
Hope I helped!
12/16, 7/16, 10/16 (not simplified, just with LCD);The LCD of the 3 fractions is 16 (from denominators) so all we have to do is multiply both the numerator by the same number that multiplies with the denominators to get 16. We leave 7/16 alone since it already has denominator of 16.
3/4 * 4 = 12/16
5/8 * 2 = 10/16
Answer: there are no like terms and there is no solutioms
Step-by-step explanation:
option 3
they are corresponding angles and are congruent