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bearhunter [10]
2 years ago
12

What is the domain of sqrt 3x-3?

Mathematics
2 answers:
makvit [3.9K]2 years ago
8 0

Answer:

{x|x ≥1} /[ 1,∞ )

Step-by-step explanation:

To find the domain, where expression is defined let

√3x-3≥0

3x-3≥0

3x≥3

x≥1

As domain is all the values of x where the expression is defined, hence the domain becomes  [1,∞) !

Natalka [10]2 years ago
7 0

For this case we must find the domain of the following expression:

\sqrt {3x-3}

The domain will be given by all the values for which the function is defined. For the given expression to be defined, the argument of the root must be positive. That is to say:

3x-3 \geq0\\3x \geq0 + 3\\3x \geq3\\\x \geq \frac {3} {3}\\x \geq1

Thus, the domain will be given by all the numbers greater than or equal to 1.

Answer:

Domain:x \geq1

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Answer:

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Step-by-step explanation:

A relation of a set of ordered pairs x and y is a function if

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  • x appears once in ordered pairs

<u><em>Examples:</em></u>

  • The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)
  • The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)
  • The domain is the set of values of x
  • The range is the set of values of y

Let us solve the question

∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}

∵ x = 1 has y = 3

∵ x = 2 has y = 3

∵ x = 3 has y = 4

∵ x = 2 has y = 5

→ One x appears twice in the ordered pairs

∵ x = 2 has y = 3 and 5

∴ The relation is not a function because one x has two values of y

∵ The domain is the set of values of x

∴ The domain = {1, 2, 3}

∵ The range is the set of values of y

∴ The range = {3, 4, 5}

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