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Diano4ka-milaya [45]
3 years ago
9

Answer th question in file please!

Mathematics
2 answers:
Sveta_85 [38]3 years ago
8 0
The anwser is A i got a little hint from the (-3) lol
elena-s [515]3 years ago
3 0

Answer:

A

Step-by-step explanation:

plug in your x each time and you get these equations , y = 0^2-3= -3 , y=1^2 -3 = -2, y= 2^2-3= 1 , y=y=3^2-3= 6

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The radius of a circle with area A can be approximated using the formula r = the square root of A/3 . Estimate the radius of a w
Arturiano [62]

Answer: 12

Step-by-step explanation:

Given:

A = 452

r = √A/3

Step 1: Substitute 452sqf for A

r = √452/3

Step 2: Solve

452 ÷ 3 = 150.66∞

√150.66∞ = 12.27∞

12.27∞ rounded to the nearest integer equal 12

3 0
3 years ago
Y=-3x + 4<br> y= 3x - 2<br><br> Solve using Elimination Method
vova2212 [387]

Answer:

x=1

y=1

Step-by-step explanation:

-3x+4=3x-2

-3x+3x+4=3x+3x-2

4=6x-2

4+2=6x-2+2

6=6x

x=1

y=3(1)-2

y=1

3 0
3 years ago
How many words can be formed by using the W,X,Y,Z if repetitions is not allowed?
Setler [38]

Answer:

24

Step-by-step explanation:

What you have here is a permutation, seeing as each element can only be used once.

We have 4 letters initially, so we can choose any 1 as our first letter. We have 4 choices for our first letter

However, once we choose our first letter, we can't use it anymore, so, for our second letter, we can only choose from the remaining 3 letters.

Furthermore, once we choose our second letter, we can only choose our 3rd letter from the remaining two letters we didn't choose yet.

Finally, our last letter will always be the one we didn't choose the last 3 times. So there is only one choice here.

Going off of this, we have four choices for the 1st letter, three choices for the 2nd letter, two choices for the 3rd letter, and one choice for the 4th letter

The way to calculate how many permutations we have without repetition is using factorials

N!

Where N is the number of elements you have.

In this case, it would be 4!

4! is 4 * 3 * 2 * 1

Which equals 24

If you notice, each number in 4! is the number of options we have for each choice. 4, then 3, and so on

5 0
3 years ago
[(2x)^x (2x)^2x]^1/x<br>how do you simplify this?
Monica [59]
Note that [ (2x)^x ]^(1/x) = 2x, and that [ (2x)^(2x) ]^(1/x) = (2x)^2 = 4x^2

Multiplying these 2 results together, we get (2x)(4x^2) = 8x^3 (answer)
5 0
3 years ago
What is the nth term of the geometric sequence 4, 8, 16, 32, ... ?
Morgarella [4.7K]
Geometric is
a_n=a_1r^{n-1}
an=nth term
a1=first term
r=common ratio
n=which term

commmon ratio is like
a1 times r=a2
4 to 8
4 times 2=8
r=2
first term is 4
therefor

a_n=4(2)^{n-1}
the nth term is 4(2)^{n-1}




3 0
4 years ago
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