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Xelga [282]
3 years ago
7

Byron needs at least 20 m rutes between

Mathematics
1 answer:
Dovator [93]3 years ago
8 0

Answer:

yes

Step-by-step explanation:

if it ends at 430 he will have 30 min before his appoionment

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What is an equation of the line that passes through the point (2, -6) and is parallel
fomenos

Answer: y=-6

Step-by-step explanation:

First convert the equation -2y= 8 into y intercept form by divide both sides by -2.

-2y = 8  

y= -4     Now that the line is in y intercept form we can now determine the slope.The slope is 0  so -4 in this case is the y intercept.

Remember lines that a parallel needs to have the same slope but different y-intercepts.

So if the slope of the line y=-4 is 0 then the slope of line that passes through the point (2,-6)  

So using the y intercept form formula which says that y=mx+b where m is the slope and b is the y-intercept, we could plot in the values for y and x and solve for b to write the equation.

y is -6 and x is 2

-6 = 0(2) + b

-6 = 0 + b

b= -6  

In this case the y intercept is -6 so since the slope is zero we will have the equation  y = -6  

5 0
3 years ago
How many hours did they drive in all please explain why
loris [4]

Answer:

The Jacobys drove 19 1/2 hours from Monday to Thursday.

7 0
3 years ago
Read 2 more answers
3. f(-4) – 3.g(-2) =
Finger [1]
I got:
-2(2f-3g)

explanation:
used communicative property
6 0
3 years ago
A certain region currently has wind farms capable of generating a total of 2200 megawatts (2.2 gigawatts) of power. Assuming win
sveta [45]

Answer:

<u>The correct answer is A. 4,818'000,000 kilowatt-hours per year and B. 481,800 households.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,200 Megawatts or 2.2 Gigawatts

2. Let's resolve the questions A and B:

Part A

Assuming wind farms typically generate 25​% of their​ capacity, how much​ energy, in​ kilowatt-hours, can the​ region's wind farms generate in one​ year?

2,200 * 0.25 = 550 Megawatts

550 Megawatts = 550 * 1,000 Kilowatts = 550,000 Kilowatts

Now we calculate the amount of Kilowatts per hour, per day and per year:

550,000 Kw generated by the farms means that are capable of produce 550,000 kw per hour of energy

550,000 * 24 = 13'200,000 kilowatt-hours per day

<u>13'200,000 * 365 = 4,818'000,000 kilowatt-hours per year</u>

Part B

Given that the average household in the region uses about​ 10,000 kilowatt-hours of energy each​ year, how many households can be powered by these wind​ farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (4,818'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

<u>Amount of households =  4,818'000,000/10,000 = 481,800</u>

8 0
3 years ago
Write a compound inequality to represent all of the numbers between -4 and 6.
Oksana_A [137]
-4<n<6
...........

.........///
6 0
3 years ago
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