To find the mean you: <span>add up all the numbers, then divide by how many numbers there are. So the mean for these numbers would be: 84%
To find the median: You put the numbers in order (From least to greatest), and then find the number exactly in the middle. Here it is an even amount of numbers. No problem, just add the two numbers in the middle and then divide by 2. The answer here is: 84%
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Answer:
The probably genotype of individual #4 if 'Aa' and individual #6 is 'aa'.
Step-by-step explanation:
In a non sex-linked, dominant trait where both parents carry and show the trait and produce children that both have and don't have the trait, they would each have a genotype of 'Aa' which would produce a likelihood of 75% of children that carry the dominant traint and 25% that don't. Since the child of #1 and #2, #5, does not exhibit the trait, nor does the significant other (#6), then they both must have the 'aa' genotype. However, since #4 displays the dominant trait received from the parents, it is more likely they would have the 'Aa' genotype as by the punnet square of 'Aa' x 'Aa', 50% of their children would have the 'Aa' phenotype.
18 servings of soup he can make with the potatoes!
72 hours I hope this helps
