Answer:
symmetric matrix is the square matrix and it is equal to its transpose
Step-by-step explanation:
solution
a symmetric matrix is the square matrix and it is equal to its transpose
As A is symmetric matrix then
A = 
here only square matrices will be symmetric
and matrix A is symmetric its mean its matrices have equal dimension
and every square diagonal matrix is also symmetric when all off diagonals element is zero
symmetric matrix for all indices i and j
A = aij = aji
Answer:
-21 - 15g
Step-by-step explanation:
You just have to distribute the -3 into the expression.
-3(7 + 5g) = -21 -15g
⇒
Answer:
Domain is (8,7,6,5) and Range is (7,7,7,7)
It should be 3.5 if im correct
Answer:
x = 19/3
Step-by-step explanation:
Solve for x:
30 x = 12 x + 22 + 23 (1 + 3)
Hint: | Evaluate 1 + 3.
1 + 3 = 4:
30 x = 12 x + 22 + 4 23
Hint: | Multiply 23 and 4 together.
23×4 = 92:
30 x = 12 x + 22 + 92
Hint: | Group like terms in 12 x + 22 + 92.
Grouping like terms, 12 x + 22 + 92 = 12 x + (92 + 22):
30 x = 12 x + (92 + 22)
Hint: | Evaluate 92 + 22.
92 + 22 = 114:
30 x = 12 x + 114
Hint: | Move terms with x to the left hand side.
Subtract 12 x from both sides:
30 x - 12 x = (12 x - 12 x) + 114
Hint: | Combine like terms in 30 x - 12 x.
30 x - 12 x = 18 x:
18 x = (12 x - 12 x) + 114
Hint: | Look for the difference of two identical terms.
12 x - 12 x = 0:
18 x = 114
Hint: | Divide both sides by a constant to simplify the equation.
Divide both sides of 18 x = 114 by 18:
(18 x)/18 = 114/18
Hint: | Any nonzero number divided by itself is one.
18/18 = 1:
x = 114/18
Hint: | Reduce 114/18 to lowest terms. Start by finding the GCD of 114 and 18.
The gcd of 114 and 18 is 6, so 114/18 = (6×19)/(6×3) = 6/6×19/3 = 19/3:
Answer: x = 19/3
