Question:
A solar power company is trying to correlate the total possible hours of daylight (simply the time from sunrise to sunset) on a given day to the production from solar panels on a residential unit. They created a scatter plot for one such unit over the span of five months. The scatter plot is shown below. The equation line of best fit for this bivariate data set was: y = 2.26x + 20.01
How many kilowatt hours would the model predict on a day that has 14 hours of possible daylight?
Answer:
51.65 kilowatt hours
Step-by-step explanation:
We are given the equation line of best fit for this data as:
y = 2.26x + 20.01
On a day that has 14 hours of possible daylight, the model prediction will be calculated as follow:
Let x = 14 in the equation.
Therefore,
y = 2.26x + 20.01
y = 2.26(14) + 20.01
y = 31.64 + 20.01
y = 51.65
On a day that has 14 hours of daylight, the model would predict 51.65 kilowatt hours
Answer is
n/7
division
hope it helps
Answer:
= 4.44948
or =
<em>step by step...solving </em>
<em>10 + 4</em><em />
<em>add/subtract </em><em>² = 6</em>
<em>=10 + 4</em><em> + </em><em>² - 6</em>
<em>Refine</em>
<em>= </em><em> ² + 4</em><em> + 4</em>
<em>rewrite </em><em>↑</em><em> as </em><em>² + 2</em><em> * 2 + 2²</em>
<em>apply Perfect Square Formula (a + b)² = a² + 2ab +²</em>
<em>a = </em><em>, b=2</em>
<em>= (</em><em> + 2)²</em>
<em>= </em><em>2square </em>
<em>(the 2 square would not fit like i wanted it to)</em>
<em>apply radical rule </em><em>, assuming a ≥ 0</em>
<em>= </em><em />
posting others as picture (have an account with Symbolab to help me as well. Just taking too long to type in the step by step if you need it. all pictures have the decimal result.
73. The tens must be greater than the ones, so it has to be 64, 73, 82, or 91. It cannot be 82 or 64 because 2 is the only even prime number. 91 are 7 and 13, leaving 73 as the number.