The absolute value inequality can be decomposed into two simpler ones.
x < 0
x > -8
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Which two inequalities can be used?</h3>
Here we start with the inequality:
3|x + 4| - 5 < 7
First we need to isolate the absolute value part:
3|x + 4| < 7 + 5
|x + 4| < (7 + 5)/3
|x + 4| < 12/3
|x + 4| < 4
The absolute value inequality can now be decomposed into two simpler ones:
x + 4 < 4
x + 4 > - 4
Solving both of these we get:
x < 4 - 4
x > -4 - 4
x < 0
x > -8
These are the two inequalities.
Learn more about inequalities:
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You can use trigonometry and the tangent to get:
tan(11°)=150/x
so x=772 ft
X=12 because 73-3x=61-2x so add 3x to both to make 73=61+X then subtract 61 from both to get 12=X
You have the following data set: 10, 14, 12, 16, 13, 15, 20, 16, 10, 14. Based on the values in the given data set, which of the
kolbaska11 [484]
Trequency distribution table:
10.....2
14.....2
12.....1
16.....2
13.....1
15.....1
20....1
Answer:
The number 11 is NOT INCLUDED in the frequency distribution
Answer:
4 11/40 hope this helps :)
Step-by-step explanation:
