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2 years ago

12

A company decides to do a survey of overall employee happiness at each of its plants by choosing 100 employees to take the surve

y from each planet. Identify the population of this survey

1 answer:

Lilit [14]2 years ago

4 0

Answer:

d

Step-by-step explanation:

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You had $50. You spent 10% of the money on clothes, 20% on games, and the rest on books. How much was spent inborn books?

Sergio [31]

70% on books which is $35. So the answer is 35 .

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3 years ago

Henry's water bottle has a capacity of 1 liter. What is the capacity of Henry's water bottle in milliliters?

kondor19780726 [428]

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3 years ago

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Solve for x.<br> Your answer must be simplified.<br> 17r > -17

Snowcat [4.5K]

Hello :D

Answer:

$\boxed{R>-1}$

The answer should have a negative sign.

Step-by-step explanation:

First, you do is divide by 17 from both sides of an equation.

$\frac{17r}{17}>\frac{-17}{17}$

Then, you simplify and solve to find the answer.

$-17\div17=-1$

$\boxed{R>-1}$ , which is our answer.

I hope this helps you!

Have a great day! :D

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2 years ago

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Ratio of AC:CB???<br> .———.—————.

erma4kov [3.2K]

Answer:

2:3 I think

Step-by-step explanation:

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2 years ago

Match each interval with its corresponding average rate of change for q(x) = (x + 3)2. 1. -6 ≤ x ≤ -4 1 2. -3 ≤ x ≤ 0 -4 3. -6 ≤

MrMuchimi

The average rate of change of a function f(x) in an interval, a < x < b is given by
$\frac{f(b) - f(a)}{b - a}$

Given q(x) = (x + 3)^2

1.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -4 is given by $\frac{q(-4)-q(-6)}{-4-(-6)} = \frac{(-4+3)^2-(-6+3)^2}{-4+6} = \frac{1-9}{2} = \frac{-8}{2} =-4$

2.) The average rate of change of q(x) in the interval -3 ≤ x ≤ 0 is given by $\frac{q(0)-q(-3)}{0-(-3)} = \frac{(0+3)^2-(-3+3)^2}{0+3} = \frac{9-0}{3} = \frac{9}{3} =3$

3.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-6)}{-3-(-6)} = \frac{(-3+3)^2-(-6+3)^2}{-3+6} = \frac{0-9}{3} = \frac{-9}{3} =-3$

4.) The average rate of change of q(x) in the interval -3 ≤ x ≤ -2 is given by $\frac{q(-2)-q(-3)}{-2-(-3)} = \frac{(-2+3)^2-(-3+3)^2}{-2+3} = \frac{1-0}{1} = \frac{1}{1} =1$

5.) The average rate of change of q(x) in the interval -4 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-4)}{-3-(-4)} = \frac{(-3+3)^2-(-4+3)^2}{-3+4} = \frac{0-1}{1} = \frac{-1}{1} =-1$

6.) The average rate of change of q(x) in the interval -6 ≤ x ≤ 0 is given by $\frac{q(0)-q(-6)}{0-(-6)} = \frac{(0+3)^2-(-6+3)^2}{0+6} = \frac{9-9}{6} = \frac{0}{6} =0$

3 0

2 years ago

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