Answer:
Cell cycle checkpoints are checking for malformations in the cell that could be potentially dangerous later down the line.
Explanation:
Answer:
E) Either anaphase I or II
Explanation:
Failure of segregation of homologous chromosomes during anaphase I or failure of segregation of sister chromatids during anaphase II leads to the presence of the abnormal number of chromosomes in resultant gametes. In the given example, the egg mother cell with 48 chromosomes (24 pairs) would enter meiosis I but the failure of one pair of homologous chromosomes to segregate from each other followed by normal meiosis II would result in the formation of two gametes with one extra chromosome and two gametes with one less chromosome.
On the other hand, if the nondisjunction occurs at anaphase II of meiosis II, two normal gametes, one gamete with one extra chromosome and one gamete with one less chromosome will be formed. Therefore, nondisjunction at anaphase I or anaphase II would have resulted in the production of eggs with one extra chromosome.
Answer:
I.
4) The deoxygenated blood then travels through the veins and enters the right side of the heart.
1) The blood leaves the heart through the aorta.
2) The blood travels throughout the body via the arteries to the capillaries.
3) In the capillaries, the exchange of nutrients and gases occurs. Oxygen is absorbed by the cells while carbon dioxide is released into the blood.
II.
2) Exchange of gases happens as oxygen is received by the blood and carbon dioxide is released.
1) The deoxygenated blood flows from the right side of the heart to go to the lungs.
3) The oxygenated blood then returns to the left side of the heart.
Explanation:
To check your answer at least twice
Answer:
by convection because convection is the transfer of heat due to indensity
